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Full Discussion: Perl code help
Top Forums Shell Programming and Scripting Perl code help Post 302881779 by rangarasan on Wednesday 1st of January 2014 08:51:18 AM
Old 01-01-2014
Hi,,

Try something like this..


Code:
my @allipsfound ;
my %ips = ();
for my $elem (@gatches) {
    my ($ip) = split ":",$elem;
    $ips{$ip} = 1;
}
print join('\n', sort keys %ips), "\n";

This User Gave Thanks to rangarasan For This Post:
 

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Heap::Elem::NumRev(3pm) 				User Contributed Perl Documentation				   Heap::Elem::NumRev(3pm)

NAME
Heap::Elem::NumRev - Reversed Numeric Heap Elements SYNOPSIS
use Heap::Elem::NumRev( NumRElem ); use Heap::Fibonacci; my $heap = Heap::Fibonacci->new; my $elem; foreach $i ( 1..100 ) { $elem = NumRElem( $i ); $heap->add( $elem ); } while( defined( $elem = $heap->extract_top ) ) { print "Largest is ", $elem->val, " "; } DESCRIPTION
Heap::Elem::NumRev is used to wrap numeric values into an element that can be managed on a heap. The top of the heap will have the largest element still remaining. (See Heap::Elem::Num if you want the heap to always return the smallest element.) The details of the Elem interface are described in Heap::Elem. The details of using a Heap interface are described in Heap. AUTHOR
John Macdonald, john@perlwolf.com COPYRIGHT
Copyright 1998-2007, O'Reilly & Associates. This code is distributed under the same copyright terms as perl itself. SEE ALSO
Heap(3), Heap::Elem(3), Heap::Elem::Num(3). perl v5.8.8 2007-10-23 Heap::Elem::NumRev(3pm)
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