I have a small program which needs to pass variable dynamically to form the name of a second variable whose value wil be passed on to a third variable.
***************** Program Start ******************
***************** Program End ******************
List of files present in the /loc1 are as below
content of filepattern.txt are as below
when i execute the program, i keep getting this error
Please let me know if i am doing something wrong. or is there an alternate way to achieve this without having to use to much variables.
expected output is:
Last edited by bartus11; 12-30-2013 at 11:50 AM..
Reason: Please use code tags
Evening all,
Have been trying to create the following environment variable:
${MD_SYSTEM}_ZZ_EMAIL_SUPPORT="myname@domain.com"
However when the script that contains the above is executed it returns:
ksh: MDQA_ZZ_EMAIL_SUPPORT=myname@domain.com: not found
Is what I'm trying to do... (2 Replies)
I would like to know how to pass a variable inside a variable to a function.
sample code below
--------------
for x in 1 9
do
check_null $C$x ##call function to check if the value is null
if
then
echo "line number:$var_cnt,... (2 Replies)
Any help would be great. I know this is a dumb way of doing this, but I would like to know if there is a solution doing it this way. I'm very new at this and I'd like to learn more. Thanks! :D:D
count=0
while ; do
echo "enter your name"
read name_$count
let count=count+1
done
... (2 Replies)
I found one post in another site with a solution for my problem
the below solution should explain what I want.
#!/bin/sh
first="one"
second="two"
third="three"
myvar="first"
echo ${!myvar}
But this gives error 'bad substitution'
System info
SunOS sundev2 5.9... (3 Replies)
Hi all,
I’m very new to UNIX programming. I have a question on dynamic variable
1. I’m having delimited file (only one row). First of all, I want to count number of columns based on delimiter. Then I want to create number of variables equal to number of fields.
Say number of... (5 Replies)
I need some variable help
TEMP1=Jane
TEMP2=Sue
X=1
eval USER=TEMP${X}
echo $USER
This gives output USER1
I would like to get Jane
I have tried
eval USER='TEMP${X}'
eval USER="TEMP${X}"
eval USER=`TEMP${X}` (3 Replies)
Hi guys.
i have a requirment as below.
I have a scripts which perform for loop
for i in /backup/logs -- it will give all the logs file
SC_RIO_RWVM_20120413064217303.LOG
SC_RIO_RWXM_20120413064225493.LOG
SC_RIO_RXXM_20120413064233273.LOG
...
do
open script.sh ---- in this file... (3 Replies)
I am trying to create some variables based on the input by the user, say if user entered 3 then 3 variables and if 5 then 5 variables.
I am using a for loop
for (( i=1; i <= $num; i++ ))
do
x="num"
x+=$i
done
When i am using echo $x it will show num1 but now how to create variables... (3 Replies)
I have a below syntax its working fine...
var12=$(ps -ef | grep apache | awk '{print $2,$4}')
Im getting expected output as below:
printf "%b\n" "${VAR12}"
dell 123
dell 456
dell 457
Now I wrote a while loop.. the output of VAR12 should be passed as input parameters to while loop and results... (5 Replies)
Hello,
I'm trying to build a small script to store a command into a dynamic variable, and I have trouble assigning the variable.
#!/bin/bash
declare -a var1array=("value1" "value2" "value3")
var1arraylength=${#var1array}
for (( i=1; i<${var1arraylength}+1; i++ ));
do
mkdir... (7 Replies)
Discussion started by: alex2005
7 Replies
LEARN ABOUT DEBIAN
incr
incr(3tcl) Tcl Built-In Commands incr(3tcl)__________________________________________________________________________________________________________________________________________________NAME
incr - Increment the value of a variable
SYNOPSIS
incr varName ?increment?
_________________________________________________________________DESCRIPTION
Increments the value stored in the variable whose name is varName. The value of the variable must be an integer. If increment is supplied
then its value (which must be an integer) is added to the value of variable varName; otherwise 1 is added to varName. The new value is
stored as a decimal string in variable varName and also returned as result.
Starting with the Tcl 8.5 release, the variable varName passed to incr may be unset, and in that case, it will be set to the value incre- |
ment or to the default increment value of 1.
EXAMPLES
Add one to the contents of the variable x:
incr x
Add 42 to the contents of the variable x:
incr x 42
Add the contents of the variable y to the contents of the variable x:
incr x $y
Add nothing at all to the variable x (often useful for checking whether an argument to a procedure is actually integral and generating an
error if it is not):
incr x 0
SEE ALSO expr(3tcl)KEYWORDS
add, increment, variable, value
Tclincr(3tcl)