Sponsored Content
Top Forums Shell Programming and Scripting Regular expression as a variable Post 302879566 by 3therk1ll on Friday 13th of December 2013 06:33:35 AM
Old 12-13-2013
Regular expression as a variable

I'm trying to use a series of regular expressions as variables but can't get it to behave properly.
You can see below what I'm trying to do.
Here with lowercase a-z and the same with uppercase, numbers 0-9 and again with a set of special characters, without having to type out every single character.
All variations on the below example

Code:
echo -ne "Use a-z (Lowercase) y/n: "
read UPCASE
    case $LOWCASE in
        [yY])
        LOWCASE2='[ a-z ]'
        ;;
        
        [nN])
        echo
        ;;
    esac
echo

Desired output:
Code:
echo $LOWCASE2

Should print out a through to z
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

regular expression using a variable

hello, I use AIX with ISM PILOT, I want to match something with a varible like this : $variable = 10 #this variable is the number of the job "$variable STARTED" # the pattern how can use this variable to match it with the word STARTED Tanks (0 Replies)
Discussion started by: barribar
0 Replies

2. Shell Programming and Scripting

compare variable against regular expression?

is it possible? if so, how? i want to check a variable whether is it a number or letter in an if-else statement (6 Replies)
Discussion started by: finalight
6 Replies

3. Shell Programming and Scripting

Awk's variable in regular expression

Anyone know how I will use awk's variable in a regular expression? This line of code of mine is working, the value PREMS should be a variable: awk '$1 ~ /PREMS/ { if(length(appldata)+2 >= length($1)) print $0; }' appldata=$APPLDATA /tmp/file.tmp The value of APPLDATA variable is PREMS. ... (2 Replies)
Discussion started by: Orbix
2 Replies

4. Shell Programming and Scripting

AWK - compare $0 to regular expression + variable

Hi, I have this script: awk -v va=45 '$0~va{print}' flo2 That returns: "4526745 1234 " (this is the only line of the file "flo2". However, I would like to get "va" to match the begining of the line, so that is "va" is different than 45 (eg. 67, 12 ...) I would not have any output. That... (3 Replies)
Discussion started by: jolecanard
3 Replies

5. Shell Programming and Scripting

Passing Variable to Regular Expression

Hi All, Below is a sample code: print "Enter the Name: "; my $Name = <>; print "Word is $Name"; open (FH,"AIDNameList.txt"); while (<FH>) { my $line; print "Word is $Name"; for $line(<FH>)... (12 Replies)
Discussion started by: jisha
12 Replies

6. Programming

Perl: How to read from a file, do regular expression and then replace the found regular expression

Hi all, How am I read a file, find the match regular expression and overwrite to the same files. open DESTINATION_FILE, "<tmptravl.dat" or die "tmptravl.dat"; open NEW_DESTINATION_FILE, ">new_tmptravl.dat" or die "new_tmptravl.dat"; while (<DESTINATION_FILE>) { # print... (1 Reply)
Discussion started by: jessy83
1 Replies

7. Shell Programming and Scripting

passing a regex as variable to awk and using that as regular expression for search

Hi All, I have a sftp session log where I am transferring multi files by issuing "mput abc*.dat". The contents of the logfile is below - ################################################# Connecting to 10.75.112.194... Changing to: /home/dasd9x/testing1 sftp> mput abc*.dat Uploading... (7 Replies)
Discussion started by: k_bijitesh
7 Replies

8. UNIX for Dummies Questions & Answers

grep with variable and regular expression

i have a command line like this in csh script grep -i "$argv$" which i wanted to select the line ending with string provided as argument but it couldn't interpret the '$' (ending with).. any help? (3 Replies)
Discussion started by: ymc1g11
3 Replies

9. UNIX for Advanced & Expert Users

sed: -e expression #1, char 0: no previous regular expression

Hello All, I'm trying to extract the lines between two consecutive elements of an array from a file. My array looks like: problem_arr=(PRS111 PRS213 PRS234) j=0 while } ] do k=`expr $j + 1` sed -n "/${problem_arr}/,/${problem_arr}/p" problemid.txt ---some operation goes... (11 Replies)
Discussion started by: InduInduIndu
11 Replies

10. Shell Programming and Scripting

How to store regular expression in a variable?

Hi, Im facing a weird behavior storing regular expression in a vaiable. Let us consider >file_name=CTP02_*.tar when I echo the above variable its displaying below which is file CTP02_*tar but when I create a file with name CTP02_1234.tar, and when I echo $file_name its showing... (3 Replies)
Discussion started by: rdineshredy
3 Replies
ECHO(1) 						    BSD General Commands Manual 						   ECHO(1)

NAME
echo -- write arguments to the standard output SYNOPSIS
echo [-n] [string ...] DESCRIPTION
The echo utility writes any specified operands, separated by single blank (' ') characters and followed by a newline (' ') character, to the standard output. The following option is available: -n Do not print the trailing newline character. This may also be achieved by appending 'c' to the end of the string, as is done by iBCS2 compatible systems. Note that this option as well as the effect of 'c' are implementation-defined in IEEE Std 1003.1-2001 (``POSIX.1'') as amended by Cor. 1-2002. Applications aiming for maximum portability are strongly encouraged to use printf(1) to sup- press the newline character. Some shells may provide a builtin echo command which is similar or identical to this utility. Most notably, the builtin echo in sh(1) does not accept the -n option. Consult the builtin(1) manual page. EXIT STATUS
The echo utility exits 0 on success, and >0 if an error occurs. SEE ALSO
builtin(1), csh(1), printf(1), sh(1) STANDARDS
The echo utility conforms to IEEE Std 1003.1-2001 (``POSIX.1'') as amended by Cor. 1-2002. BSD
April 12, 2003 BSD
All times are GMT -4. The time now is 08:17 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy