Sponsored Content
Top Forums Shell Programming and Scripting Remove carriage return from the variable Post 302878411 by Akshay Hegde on Friday 6th of December 2013 03:25:22 AM
Old 12-06-2013
You could use awk also
Code:
$ a="2.80985e+09\r\r\n"
$ echo $a
2.80985e+09\r\r\n

$ b=$(awk -v var=$a 'BEGIN{print var+10000000}')
$ echo $b
2819850000

 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

Remove a carriage return at end of variable

Is there a command in unix to remove a carriage return character(^M) at the end of a variable value? (5 Replies)
Discussion started by: flagship99
5 Replies

2. UNIX for Dummies Questions & Answers

To remove carriage return between the line

Hi, I have a situation where I need to remove the carriage return between the lines. For.eg. The input file: 1,ad,"adc sdfd",edf 2,asd,"def fde",asd The output file should be 1,ad,adc sdfd,edf 2,asd,def fde,asd Thanks Shash (5 Replies)
Discussion started by: shash
5 Replies

3. Shell Programming and Scripting

Insert a line including Variable & Carriage Return / sed command as Variable

I want to instert Category:XXXXX into the 2. line something like this should work, but I have somewhere the wrong sytanx. something with the linebreak goes wrong: sed "2i\\${n}Category:$cat\n" Sample: Titel Blahh Blahh abllk sdhsd sjdhf Blahh Blah Blahh Blahh Should look like... (2 Replies)
Discussion started by: lowmaster
2 Replies

4. Shell Programming and Scripting

sqlplus returning value - remove carriage return '\r' - Please help

Guys - Simple code, i am trying to get a number back from sqlplus call to a query. After that, i need to use that number in a loop. --------------------------------- #!/bin/ksh VALUE=`sqlplus -silent sh/password@sh <<END set pagesize 0 feedback off verify off heading off echo off select... (10 Replies)
Discussion started by: sunshine1974
10 Replies

5. UNIX for Dummies Questions & Answers

Remove ^M (carriage return) with string manipulation

Hello, I want remove ^M at end of my files line if I use command : tr -d '\r' <inp>out it work fine but get I the same result by manipulating the string ? I want this because in my text file I manipulate some other part I have input "the cat^M" I want output "the cat" I have made... (3 Replies)
Discussion started by: aquila_1
3 Replies

6. Shell Programming and Scripting

Remove carriage return in a record

Hi all gurus, I need help in removing carriage return existed within a record delimited by pipe <|>. Sample: A_01|Test1|Testing1|Remarks1 A_02|Test2|Test ing2|Remarks2 A_03|Test3|Testing3| Remarks3 Desire output: A_01|Test1|Testing1|Remarks1 A_02|Test2|Testing2|Remarks2... (10 Replies)
Discussion started by: agathaeleanor
10 Replies

7. Shell Programming and Scripting

Awk to remove carriage return from 65th field

Hi, I have a pipe delimited file. There are around 700 columns in the file. The 65th column has carriage return which is causing read issue with our ETL process. I would like to replace the new line characters in 65th field with "nothing" i have return the following code and need help to... (7 Replies)
Discussion started by: pinnacle
7 Replies

8. UNIX for Dummies Questions & Answers

Remove carriage return

I need to remove the carriage return comes inbetween the record. Need to have CR only at the end. I used the below command. tr -d '\n' < filewithcarriagereturns > filewithoutcarriagereturns But its removing all the CR and giving one line output. Input File: 12345 abcdegh... (11 Replies)
Discussion started by: srvn_saru
11 Replies

9. Shell Programming and Scripting

Remove Carriage Return (CRLF) within double quotes

How to remove Carriage Return (CRLF) within double quotes in a file. There are multiple CRLFs within double quotes. We are on Ubuntu 14.04.2 LTS. The file that we are importing is a csv file from unix to windows and the file was formatted to unix2dos. Therefore all lines in the file all have... (12 Replies)
Discussion started by: covina
12 Replies

10. Shell Programming and Scripting

Remove carriage return and append the next line

Hi All, My requirement is to remove the carriage return in from the lines which i am reading if the length is lesser than 1330 and append the next line with it. Below is the realistic example of file structure. Input file: Blah blah blah blah Blah blah blah blah Blah blah blah blah Blah... (16 Replies)
Discussion started by: mad man
16 Replies
Devel::Refcount(3pm)					User Contributed Perl Documentation				      Devel::Refcount(3pm)

NAME
"Devel::Refcount" - obtain the REFCNT value of a referent SYNOPSIS
use Devel::Refcount qw( refcount ); my $anon = []; print "Anon ARRAY $anon has " . refcount($anon) . " reference "; my $otherref = $anon; print "Anon ARRAY $anon now has " . refcount($anon) . " references "; DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value. FUNCTIONS
$count = refcount($ref) Returns the reference count of the object being pointed to by $ref. COMPARISON WITH SvREFCNT This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed, whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH, CODE, GLOB and Regexp types) as well. Consider the following example program: use Devel::Peek qw( SvREFCNT ); use Devel::Refcount qw( refcount ); sub printcount { my $name = shift; printf "%30s has SvREFCNT=%d, refcount=%d ", $name, SvREFCNT($_[0]), refcount($_[0]); } my $var = []; printcount 'Initially, $var', $var; my $othervar = $var; printcount 'Before CODE ref, $var', $var; printcount '$othervar', $othervar; my $code = sub { undef $var }; printcount 'After CODE ref, $var', $var; printcount '$othervar', $othervar; This produces the output Initially, $var has SvREFCNT=1, refcount=1 Before CODE ref, $var has SvREFCNT=1, refcount=2 $othervar has SvREFCNT=1, refcount=2 After CODE ref, $var has SvREFCNT=2, refcount=2 $othervar has SvREFCNT=1, refcount=2 Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this case. Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it. After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the new anonymous CODE block. PURE-PERL FALLBACK An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in pure perl using the "B" module is used instead. This will behave identically, but is much slower. Rate pp xs pp 225985/s -- -66% xs 669570/s 196% -- SEE ALSO
o Test::Refcount - assert reference counts on objects AUTHOR
Paul Evans <leonerd@leonerd.org.uk> perl v5.14.2 2011-11-15 Devel::Refcount(3pm)
All times are GMT -4. The time now is 10:56 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy