Hello All,
I have a string "CP_STATUS OSSRC_R6_0_Shipment_R1H_CU AOM_901046 R1H_LLSV1_2008031", and I just want to extract LLSV1, but I dont get the expected result when using the sed command below.
# echo "CP_STATUS OSSRC_R6_0_Shipment_R1H_CU AOM_901046 R1H_LLSV1_2008031" | awk '{print... (4 Replies)
Hi
i want to search two pattern on same line and replace onther pattern..
INPut file
aaaa bbbbb nnnnnn ttttt
cccc bbbbb nnnnnn ppppp
dddd ccccc nnnnnn ttttt
ffff bbbbb oooooo ttttt
now i want replace this matrix like.. i want search for "bbbbb","nnnnnn" and search and replace for... (4 Replies)
Hi,
i want to remove a certain pattern when i type pwd.
pwd will look like this:
..../....../....../Pat_logs/..../....../...../......
the dotted lines are just random directory names,
i want it to remove the "Pat_logs/...../....../....../" part
so for example:
... (8 Replies)
I need this.
aaa
OOOOO
bbb
ccc
OOOOO
ddd
fff
ggg
OOOOO
iii
OOOOO
I need all OOOOO replaced with PPPPP, but only change after the pattern ggg. So the first two OOOOO should not be changed.
OUTPUT should be :-
aaa (2 Replies)
I have a pattern
username:x:32005:32006::/usr/local/user:/bin/bash
I need to match the line containing username and replace /bin/bash with /usr/local/my/bin/noshell
So it becomes
username:x:32005:32006::/usr/local/user:/usr/local/my/bin/noshell (7 Replies)
Hi,
I have a requirement where I need to replace a string in a line and this line will be identified by search criteria on previous line:
E.g.:
I have an xml file and Contents as below:
<Root>
<NameValue>
<name>Global/Text/Data</name>
<value>This is valid... (14 Replies)
Hi, I am a rookie of Linux.
I have a problem on how can I replace a certain pattern in Linux with nothing. Can anyone help me?:(
sample.txt:
<binding>App189
ABC SampleMachine1 ABC
XXX
YYY
ZZZ
</binding>
<binding>App190
ABC SampleMachine2 ABC
XXX
YYY
ZZZ
</binding>
<binding>App191... (3 Replies)
Hi,
Need help to extract a pattern using sed or cut or any other means.
Input
'name1',1234567890
'name2',2222222222
'name3',3333333333
Expected output
name1,1234567890
name2,2222222222
name3,3333333333 (3 Replies)
Hi experts, I'm looking for a unix solution to replacing "NA" within a matrix with the mean of the column:
$cat file
ID a b c d
day 10 5 100 50
cat 20 6 200 50
dog NA 8 NA 50
car 15 NA NA ... (3 Replies)
Not able to paste my content. Please see the attachment :-( (2 Replies)
Discussion started by: vivek d r
2 Replies
LEARN ABOUT CENTOS
do
DO(7) PostgreSQL 9.2.7 Documentation DO(7)NAME
DO - execute an anonymous code block
SYNOPSIS
DO [ LANGUAGE lang_name ] code
DESCRIPTION
DO executes an anonymous code block, or in other words a transient anonymous function in a procedural language.
The code block is treated as though it were the body of a function with no parameters, returning void. It is parsed and executed a single
time.
The optional LANGUAGE clause can be written either before or after the code block.
PARAMETERS
code
The procedural language code to be executed. This must be specified as a string literal, just as in CREATE FUNCTION. Use of a
dollar-quoted literal is recommended.
lang_name
The name of the procedural language the code is written in. If omitted, the default is plpgsql.
NOTES
The procedural language to be used must already have been installed into the current database by means of CREATE LANGUAGE. plpgsql is
installed by default, but other languages are not.
The user must have USAGE privilege for the procedural language, or must be a superuser if the language is untrusted. This is the same
privilege requirement as for creating a function in the language.
EXAMPLES
Grant all privileges on all views in schema public to role webuser:
DO $$DECLARE r record;
BEGIN
FOR r IN SELECT table_schema, table_name FROM information_schema.tables
WHERE table_type = 'VIEW' AND table_schema = 'public'
LOOP
EXECUTE 'GRANT ALL ON ' || quote_ident(r.table_schema) || '.' || quote_ident(r.table_name) || ' TO webuser';
END LOOP;
END$$;
COMPATIBILITY
There is no DO statement in the SQL standard.
SEE ALSO
CREATE LANGUAGE (CREATE_LANGUAGE(7))
PostgreSQL 9.2.7 2014-02-17 DO(7)