Hi All,
I am new to shell script.
I wrote a very small script that takes only digits as input-
but there is some problem in that.can you help me in debugging that.
#!/bin/ksh
echo "Digits as input"
read number
digit='eval '
if ]
then
echo "Entered number is a digit"
else
echo... (2 Replies)
I want to check the argument in KSH. If the user type in the prompt 'find 3' it will format 3 to 003 to match the data in the text file. Same as with 10 to 010. Always begins with 0.
eg.
>find 3
Output:
003
>find 30
Output:
030 (7 Replies)
hi group,
How can I count total number of 5's which are continuous in the end. i.e. in the below string, the o/p should be 4
I just know to calculate total number of 5's
$ echo "95952325555" | awk -F "5" '{print NF-1}'
6 (3 Replies)
Hi Folks
Probably an easy one here but how do I get a sequence to get used as mentioned. For example in the following I want to automatically create files that have a 2 digit number at the end of their names:
m@pyhead:~$ for x in $(seq 00 10); do touch file_$x; done
m@pyhead:~$ ls file*... (2 Replies)
Hello all! I've looked all over the internet and this site and have come up a loss with an easy way to make a bash script to do what I want to do. I have a file with a naming convention as follows:
2012-01-18 string of words here 123.jpg
2012-01-18 string of words here 1234.jpg
2012-01-18... (2 Replies)
Hi,
How I can replace last 8 ZEROS with 22991231?
19523479811841494432A2013052700000000
19523479811730333980A2013052700000000
19523479811417044397A2013052700000000
19523479811205895810C2013010120130131
A9523479811205895810A2013020120130228
19523479811205895810I2013030120130331... (9 Replies)
Is there any program that can create 6 digit numbers with:
(DIGIT_1)+(DIGIT_2)+(DIGIT_3)+(DIGIT_4)+(DIGIT_5)+(DIGIT_6)=10
Any perl or C also can. Anyone can help me? Thank you (6 Replies)
e.g.
File name: File.txt
cat File.txt
Result:
#INBOUND_QUEUE=FAQ1
INBOUND_QUEUE=FAQ2
I want to get the value for one which is not commented out.
Thanks, (3 Replies)
Hello everybody
I'm a little beginer for shell script as I started last night...
I have this script
cat fichier.txt | while read l ; do
#echo $l
echo $x
x=$(( $x + 1 ))
done
it's return
1
2
3
4 (4 Replies)
Hi All ,
I am having an input file as stated below
5728 U_TOP_LOGIC/U_CM0P/core/u_cortexm0plus/u_top/u_sys/u_core/r03_q_reg_20_/Q 011
611 U_TOP_LOGIC/U_CM0P/core/u_cortexm0plus/u_top/u_sys/u_core/r04_q_reg_20_/Q 011
3486... (4 Replies)
Discussion started by: kshitij
4 Replies
LEARN ABOUT DEBIAN
io::async::timer::absolute
IO::Async::Timer::Absolute(3pm) User Contributed Perl Documentation IO::Async::Timer::Absolute(3pm)NAME
"IO::Async::Timer::Absolute" - event callback at a fixed future time
SYNOPSIS
use IO::Async::Timer::Absolute;
use POSIX qw( mktime );
use IO::Async::Loop;
my $loop = IO::Async::Loop->new;
my @time = gmtime;
my $timer = IO::Async::Timer::Absolute->new(
time => mktime( 0, 0, 0, $time[4]+1, $time[5], $time[6] ),
on_expire => sub {
print "It's midnight
";
$loop->stop;
},
);
$loop->add( $timer );
$loop->run;
DESCRIPTION
This subclass of IO::Async::Timer implements one-shot events at a fixed time in the future. The object waits for a given timestamp, and
invokes its callback at that point in the future.
For a "Timer" object that waits for a delay relative to the time it is started, see instead IO::Async::Timer::Countdown.
EVENTS
The following events are invoked, either using subclass methods or CODE references in parameters:
on_expire
Invoked when the timer expires.
PARAMETERS
The following named parameters may be passed to "new" or "configure":
on_expire => CODE
CODE reference for the "on_expire" event.
time => NUM
The epoch time at which the timer will expire.
Once constructed, the timer object will need to be added to the "Loop" before it will work.
Unlike other timers, it does not make sense to "start" this object, because its expiry time is absolute, and not relative to the time it is
started.
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2012-10-24 IO::Async::Timer::Absolute(3pm)