Sponsored Content
Full Discussion: Integer expression expected
Top Forums Shell Programming and Scripting Integer expression expected Post 302877196 by Don Cragun on Thursday 28th of November 2013 10:27:17 PM
Old 11-28-2013
In the test:
Code:
if [ "$a1" -eq "$b1" ]

the -eq operator is used to compare numeric values and the = operator is used to compare string values. "Nov" is a string; not a number. Try:
Code:
if [ "$a1" = "$b1" ]

 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Integer Expression Expected

Cannot figure out what the error is on line #10 I was trying to change my login prompt though I've success with that this shows up as well. Here's what I have (1 Reply)
Discussion started by: moonunit
1 Replies

2. Shell Programming and Scripting

:integer expression expected

Hi, echo $i until || do read NUM if && ; then printf "$FBOLD\nInvalid number, please enter valid backup number: $FREG" fi done Getting below error : ./import_location.sh: line 234: [: : integer expression expected ./import_location.sh: line 234: [: :... (5 Replies)
Discussion started by: milink
5 Replies

3. Shell Programming and Scripting

Integer expression expected: with regular expression

CA_RELEASE has a value of 6. I need to check if that this is a numeric value. if not error. source $CA_VERSION_DATA if * ] then echo "CA_RELESE $CA_RELEASE is invalid" exit -1 fi + source /etc/ncgl/ca_version_data ++ CA_PRODUCT_ID=samxts ++ CA_RELEASE=6 ++ CA_WEEK_NO=7 ++... (3 Replies)
Discussion started by: ketkee1985
3 Replies

4. UNIX for Dummies Questions & Answers

Integer Expression Expected!?!?

Ok, so I am beggining a script to factor the time difference from when a user logs on to current time but before I can even get too far I am getting the INTEGER EXPRESSION EXPECTED error. Can someone tell me what I am doing wrong? lhour=$(who | grep "$1" | cut -c30,31); lmin=$(who | grep "$1"... (1 Reply)
Discussion started by: losingit
1 Replies

5. Shell Programming and Scripting

Error: integer expression expected

root@server01 # df -h | grep /tmp | awk {'print $3}' 252M root@server01 # root@server01 # cat /usr/local/tmpchk.sh #!/bin/sh x=`df -h | grep /tmp | awk {'print $3}'` if ; then rm -fr /tmp/somefolder/ else echo "its small" (2 Replies)
Discussion started by: fed.linuxgossip
2 Replies

6. Shell Programming and Scripting

Integer expression expected

Newb here echo "$yesterdaysclose" echo "$close" if ; then echo "stocks moving up" elif ; then echo "stock is moving down" else echo "no change" fi seems to evaluate the floating decimal correctly however returns ./shellscript1.sh: line 17: [: : integer expression expected... (3 Replies)
Discussion started by: harte
3 Replies

7. Shell Programming and Scripting

Integer expression expected

hi Guys, when i run the below script its showing error "integer expression expected" script pasted below: #!/bin/sh for i in {1..$2} do if then scp server1:/root/file.2012-$1-0$i . else scp server1:/root/file.2012-$1-$i . fi done (8 Replies)
Discussion started by: ganga39
8 Replies

8. Shell Programming and Scripting

Integer expression expected

Hi, I have placed the script and running successfully on AIX However in Linux it throws integer expression expected Could some one please help me to fix this MaxThreshold4alert=`echo "$MaxCapacitycnt*(80/100)" |bc -l` echo $MaxThreshold4alert Error: 40.00000000000000000000: integer... (2 Replies)
Discussion started by: ajothi
2 Replies

9. Shell Programming and Scripting

Integer expression expected

I need some help with this if but then it says line 11: I don't know what I'm doing wrong (1 Reply)
Discussion started by: margg
1 Replies

10. Shell Programming and Scripting

Integer expression expected

Hello , This is the piece of the code which is giving me trouble if ;then exit_proc "${SOURCEDIR}/${OUT_FILE} does not exists or not readable" 2 else word_count=`wc -l < ${SOURCEDIR}/$OUT_FILE` fi if ;then exit_proc "Word_count is more than allowed limit" 1 else... (6 Replies)
Discussion started by: Sri3001
6 Replies
CAL(1)								   User Commands							    CAL(1)

NAME
cal - display a calendar SYNOPSIS
cal [options] [[[day] month] year] DESCRIPTION
cal displays a simple calendar. If no arguments are specified, the current month is displayed. OPTIONS
-1, --one Display single month output. (This is the default.) -3, --three Display prev/current/next month output. -s, --sunday Display Sunday as the first day of the week. -m, --monday Display Monday as the first day of the week. -j, --julian Display Julian dates (days one-based, numbered from January 1). -y, --year Display a calendar for the current year. -V, --version Display version information and exit. -h, --help Display help screen and exit. PARAMETERS
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: cal 89 will not display a calendar for 1989. Two parameters denote the month (1 - 12) and year. Three parameters denote the day (1-31), month and year, and the day will be highlighted if the calendar is displayed on a terminal. If no parameters are specified, the current month's calendar is displayed. A year starts on Jan 1. The first day of the week is determined by the locale. The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref- ormation (although a few did not recognize it until the early 1900's). Ten days following that date were eliminated by the reformation, so the calendar for that month is a bit unusual. HISTORY
A cal command appeared in Version 6 AT&T UNIX. AVAILABILITY
The cal command is part of the util-linux package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux/. util-linux June 2011 CAL(1)
All times are GMT -4. The time now is 05:11 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy