Variable in bash help Post: 302877082

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

passing variable from bash to perl from bash script

Hi All, I need to pass a variable to perl script from bash script, where in perl i am using if condition. Here is the cmd what i am using in perl FROM_DATE="06/05/2008" TO_DATE="07/05/2008" "perl -ne ' print if ( $_ >="$FROM_DATE" && $_ <= "$TO_DATE" ) ' filename" filename has...

2. Shell Programming and Scripting

bash and ksh: variable lost in loop in bash?

Hi, I use AIX (ksh) and Linux (bash) servers. I'm trying to do scripts to will run in both ksh and bash, and most of the time it works. But this time I don't get it in bash (I'm more familar in ksh). The goal of my script if to read a "config file" (like "ini" file), and make various report....

3. Shell Programming and Scripting

BASH get variable according to name of another variable

Just started BASH scripting, and I tried to make a script 'args' to display all of the arguments that I give to it. #!/bin/bash if then echo "No arguments specified." fi val= for ((i=1; i <= $# ; i++)) do eval "\$val=\$$i" echo "Argument number $i is $var." done However...

4. Shell Programming and Scripting

Using the value of one variable to name another variable (in bash)

Hello all, I'm working on a script, and as part of it, I'm trying to create a loop that will run through a stored piece of information a certain number of times pulling out information, and each time create a variable with a unique name that will store that information. I'm sure it's a simple...

5. Shell Programming and Scripting

[Bash]variable does not keep its value

Hello all, I have this shell script, but do not understand why the variables inside the if block does not keep its value outside. Is it because of the pipe ? How can i fix this problem ? Thank you for helping. local alarm="" local num_alarm=0 local -a alarms ...

6. Shell Programming and Scripting

bash - define a variable

Hello, I would like to define a variable based on another variable: a=5 b$a=100 This does not work. What is the right way to do it? Thanks ---------- Post updated at 07:37 PM ---------- Previous update was at 07:33 PM ---------- Found my answer with the search function (did not...

7. Shell Programming and Scripting

bash - Variable made of variable

Hello, I am struggling with using variable made using "eval". a=4 eval b$a=20 echo $b$a ??? As shown above, I am trying to call back the variable "bX" assuming I do not know the value of "a". How can I do that? I tried several combinations but nothing worked. Thanks

8. Shell Programming and Scripting

Use variable in bash

$ p="1 2 5 8" $ set -- $p $ echo $3 5 $ k=3 $ echo \$${k} $3 I want the "echo \$${k}" to get the output 5 , how to modify ?

9. Shell Programming and Scripting

Bash variable within variable

Hello, Can I ask how to expand variable that contains another in bash? I need to loop variable within another one like this: RD1=testgrp RD2=testgroup RD3=testgroupfile RD4=tstgroup ... RD40=try2013 DEST=/home/king/finaldir for i in {1..40}; do mv ${RD${i}} ${DEST} done I do not...

10. Shell Programming and Scripting

Using RegEx with variable within bash if [[ ]]

I stumbled upon a problem, which I simplified to this: There is a list of numbers, stored in variable $LIST, lets use `seq 5 25` for demonstration. There is a number that should be compared against this list. For demonstration I use user input - read VALUE I am trying to compare RegEx...

LEARN ABOUT CENTOS

lessecho

LESSECHO(1)						      General Commands Manual						       LESSECHO(1)

NAME

       lessecho - expand metacharacters

SYNOPSIS

       lessecho [-ox] [-cx] [-pn] [-dn] [-mx] [-nn] [-ex] [-a] file ...

DESCRIPTION

       lessecho  is  a program that simply echos its arguments on standard output.  But any metacharacter in the output is preceded by an "escape"
       character, which by default is a backslash.

OPTIONS

       A summary of options is included below.

       -ex    Specifies "x", rather than backslash, to be the escape char for metachars.  If x is "-", no escape char is used and  arguments  con-
	      taining metachars are surrounded by quotes instead.

       -ox    Specifies "x", rather than double-quote, to be the open quote character, which is used if the -e- option is specified.

       -cx    Specifies "x" to be the close quote character.

       -pn    Specifies "n" to be the open quote character, as an integer.

       -dn    Specifies "n" to be the close quote character, as an integer.

       -mx    Specifies "x" to be a metachar.  By default, no characters are considered metachars.

       -nn    Specifies "n" to be a metachar, as an integer.

       -fn    Specifies "n" to be the escape char for metachars, as an integer.

       -a     Specifies that all arguments are to be quoted.  The default is that only arguments containing metacharacters are quoted

SEE ALSO

       less(1)

AUTHOR

       This manual page was written by Thomas Schoepf <schoepf@debian.org>, for the Debian GNU/Linux system (but may be used by others).

       Send bug reports or comments to bug-less@gnu.org.

							     Version 458: 04 Apr 2013						       LESSECHO(1)