Sponsored Content
Full Discussion: Convert Date Format
Top Forums Shell Programming and Scripting Convert Date Format Post 302877028 by cartrider on Wednesday 27th of November 2013 04:21:00 PM
Old 11-27-2013
I am not getting the expected output of 13-MAR-2013 14:24:50

Code:
elise->DEV> echo $curr_date
2013/03/13 14:24:50
elise->DEV> date +'%d-%b-%Y %H:%M:%S' -d "$curr_date"
27-Nov-2013 16:17:27
elise->DEV> date -d "$curr_date" +'%d-%b-%Y %T'clear
date: illegal option -- d
usage:  date [-u] mmddHHMM[[cc]yy][.SS]
        date [-u] [+format]
        date -a [-]sss[.fff]
elise->DEV>

 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

convert mmddyy date format to ccyyddd format??

hi, for reading a cobol indexed file i need to convert "mmddyy" date format to "ccyyddd" format. i checked the datecalc and other scripts but couldnt modify them to cater to my need:(... The datecalc gives an output which i believe is the total days till that date, but i want to convert it... (2 Replies)
Discussion started by: Bhups
2 Replies

2. UNIX for Dummies Questions & Answers

Convert date format

Hi All, Need your help in converting a date format in ksh. I'm currently working on SUN os where my script is getting a date from a table. The result returns to ksh in this format: 17-JUL-08 How do i convert this string to a date format like yyyymmdd? I tried #!/bin/ksh d="17-JUL-08"... (5 Replies)
Discussion started by: agathaeleanor
5 Replies

3. Shell Programming and Scripting

Convert Epoch time format to normal date time format in the same file

I have a file named "suspected" with series of line like these : {'protocol': 17, 'service': 'BitTorrent KRPC', 'server': '219.78.120.166', 'client_port': 52044, 'client': '10.64.68.44', 'server_port': 8291, 'time': 1226506312L, 'serverhostname': ''} {'protocol': 17, 'service': 'BitTorrent... (3 Replies)
Discussion started by: rk4k
3 Replies

4. Shell Programming and Scripting

convert date format to mysql date format in log file

I have a comma delimited log file which has the date as MM/DD/YY in the 2nd column, and HH:MM:SS in the 3rd column. I need to change the date format to YYYY-MM-DD and merge it with the the time HH:MM:SS. How will I got about this? Sample input 02/27/09,23:52:31 02/27/09,23:52:52... (3 Replies)
Discussion started by: hazno
3 Replies

5. Shell Programming and Scripting

Convert date to Unix format

Dear Expert How to convert date in format of YYYY-MM-DD HH:MM:SS to unix format using a script or command if avaliable Example "2011-05-15 18:00:00" is converted to 1330970400 I tried to use option d in date command but no use, Im using solaris 10 Thanks a lot (12 Replies)
Discussion started by: yahyaaa
12 Replies

6. Shell Programming and Scripting

convert date format

I've been using this thread: https://www.unix.com/shell-programming-scripting/58675-change-date-dd-mmm-yyyy-mm-dd-yyyy.html and https://www.unix.com/shell-programming-scripting/14655-changing-yyyy-mm-dd-ddmmyy.html and this code: on this format: 05/16/2008 18:30:49 Installation 48985and I'm... (3 Replies)
Discussion started by: dba_frog
3 Replies

7. Shell Programming and Scripting

Convert any date format into yyyy/mm/dd

How can I convert any user inputted date into yyyy/mm/dd ? For example user can input date one of the following 20120121 , 2012-01-21 ,01/21/2012,01/21/2012 etc But I need to convert any of the date entered by user into yyyy/mm/dd (2012/01/2012). Any suggestion. Thanks in advance this is... (1 Reply)
Discussion started by: ZeroHedge
1 Replies

8. Shell Programming and Scripting

awk convert date format

Could you tell me how to convert the following dates? If I have m/d/yyyy, I want to have 0m/0d/yyyy. I want my dates to always be 8 digits. In other words, I want a 0 inserted whenever the month or day is a single digit. My issue is first I need to use FS="," to get field $4 for the... (7 Replies)
Discussion started by: wbrunc
7 Replies

9. Shell Programming and Scripting

Convert string into date format

Hi, I am getting the below string as a input for date. 12/03/2013 11:02 AM I want to change this date as 03-DEC-2013 11:02 AM. Could you please help on this. Thanks Chelladurai (4 Replies)
Discussion started by: ckchelladurai
4 Replies

10. Shell Programming and Scripting

Convert date format

Hi guys I am looking to convert this kind of entry in a txt file 26/04/2008 to April 2008 Note : this is not using the date command , these are date entries in a file can i do this with sed ? Use code tags, thanks. (5 Replies)
Discussion started by: johnnybananas
5 Replies
DATETIME.SUB(3) 							 1							   DATETIME.SUB(3)

DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object

       Object oriented style

SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval) DESCRIPTION
Procedural style DateTime date_sub (DateTime $object, DateInterval $interval) Subtracts the specified DateInterval object from the specified DateTime object. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $interval - A DateInterval object RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. EXAMPLES
Example #1 DateTime.sub(3) example Object oriented style <?php $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('P10D')); echo $date->format('Y-m-d') . " "; ?> Procedural style <?php $date = date_create('2000-01-20'); date_sub($date, date_interval_create_from_date_string('10 days')); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2000-01-10 Example #2 Further DateTime.sub(3) examples <?php $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('PT10H30S')); echo $date->format('Y-m-d H:i:s') . " "; $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('P7Y5M4DT4H3M2S')); echo $date->format('Y-m-d H:i:s') . " "; ?> The above example will output: 2000-01-19 13:59:30 1992-08-15 19:56:58 Example #3 Beware when subtracting months <?php $date = new DateTime('2001-04-30'); $interval = new DateInterval('P1M'); $date->sub($interval); echo $date->format('Y-m-d') . " "; $date->sub($interval); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-03-30 2001-03-02 NOTES
DateTime.modify(3) is an alternative when using PHP 5.2. SEE ALSO
DateTime.add(3), DateTime.diff(3), DateTime.modify(3). PHP Documentation Group DATETIME.SUB(3)
All times are GMT -4. The time now is 07:59 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy