Print 4th line back from regexp Post: 302875839

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print the line immediately after a regexp; but regexp is a sentence

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I am on a Solaris 10 x86 system sample code before3 before2 before1 group after1 after2 after3 I want to grab the second line above my regexp regexp=group I want to grab ONLY the before2 line I have numerous sed and awk ways of grabbing X line below the regexp, but no luck...

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print lines AFTER lines cointaining a regexp (or print every first and fourth line)

Hi all, This should be very easy but I can't figure it out... I have a file that looks like this: @SRR057408.1 FW8Y5CK02R652T length=34 AGCAGTGGTATCAACGCAGAGTAAGCAGTGGTAT +SRR057408.1 FW8Y5CK02R652T length=34 FIIHFF6666?=:88@@@BBD:::?@ABBAAA>8 @SRR057408.2 FW8Y5CK02TBMHV length=52...

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sed print first line before regexp and all lines after

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awk to print the string between 3rd and 4th backslashs to end of line

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LEARN ABOUT LINUX

shtool-path

SHTOOL-PATH.TMP(1)					      GNU Portable Shell Tool						SHTOOL-PATH.TMP(1)

NAME

       shtool-path - GNU shtool command dealing with shell path variables

SYNOPSIS

       shtool path [-s|--suppress] [-r|--reverse] [-d|--dirname] [-b|--basename] [-m|--magic] [-p|--path path] str [str ...]

DESCRIPTION

       This command deals with shell $PATH variables. It can find a program through one or more filenames given by one or more str arguments.  It
       prints the absolute filesystem path to the program displayed on "stdout" plus an exit code of 0 if it was really found.

OPTIONS

       The following command line options are available.

       -s, --suppress
	   Supress output. Useful to only test whether a program exists with the help of the return code.

       -r, --reverse
	   Transform a forward path to a subdirectory into a reverse path.

       -d, --dirname
	   Output the directory name of str.

       -b, --basename
	   Output the base name of str.

       -m, --magic
	   Enable advanced magic search for ""perl"" and ""cpp"".

       -p, --path path
	   Search in path. Default is to search in $PATH.

EXAMPLE

	#   shell script
	awk=`shtool path -p "${PATH}:." gawk nawk awk`
	perl=`shtool path -m perl`
	cpp=`shtool path -m cpp`
	revpath=`shtool path -r path/to/subdir`

HISTORY

       The GNU shtool path command was originally written by Ralf S.  Engelschall <rse@engelschall.com> in 1998 for Apache. It was later taken
       over into GNU shtool.

SEE ALSO

       shtool(1), which(1).

18-Jul-2008							   shtool 2.0.8 						SHTOOL-PATH.TMP(1)

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

regexp to print after a field seperator

Discussion started by: ramky79

2. UNIX for Dummies Questions & Answers

print the line immediately after a regexp; but regexp is a sentence

Discussion started by: ownins

3. Shell Programming and Scripting

print 2 lines above regexp

Discussion started by: snoman1

4. Shell Programming and Scripting

print lines AFTER lines cointaining a regexp (or print every first and fourth line)

Discussion started by: kmkocot