Bash shell script undefined array item value question
Hello,
I'm new here. I test these expressions's value in my script :
(in centOS 6 )
The output result is :
Why the value of ${array["test1"]} and ${array["test2"]} is "something" instead of empty ?
Because they are not defined just as ${array["5"]}, however the value of ${array["5"]} is empty and it's correct.
Thanks in advance for your help.
Last edited by Franklin52; 11-19-2013 at 05:32 AM..
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LEARN ABOUT PHP
mysql_fetch_row
MYSQL_FETCH_ROW(3) 1 MYSQL_FETCH_ROW(3)mysql_fetch_row - Get a result row as an enumerated arraySYNOPSIS
Warning
This extension is deprecated as of PHP 5.5.0, and will be removed in the future. Instead, the MySQLi or PDO_MySQL extension should
be used. See also MySQL: choosing an API guide and related FAQ for more information. Alternatives to this function include:
omysqli_fetch_row(3)
o PDOStatement::fetch
array mysql_fetch_row (resource $result)
DESCRIPTION
Returns a numerical array that corresponds to the fetched row and moves the internal data pointer ahead.
o $
result -The result resource that is being evaluated. This result comes from a call to mysql_query(3).
Returns an numerical array of strings that corresponds to the fetched row, or FALSE if there are no more rows.
mysql_fetch_row(3) fetches one row of data from the result associated with the specified result identifier. The row is returned as an
array. Each result column is stored in an array offset, starting at offset 0.
Example #1
Fetching one row with mysql_fetch_row(3)
<?php
$result = mysql_query("SELECT id,email FROM people WHERE id = '42'");
if (!$result) {
echo 'Could not run query: ' . mysql_error();
exit;
}
$row = mysql_fetch_row($result);
echo $row[0]; // 42
echo $row[1]; // the email value
?>
Note
This function sets NULL fields to the PHP NULL value.
mysql_fetch_array(3), mysql_fetch_assoc(3), mysql_fetch_object(3), mysql_data_seek(3), mysql_fetch_lengths(3), mysql_result(3).
PHP Documentation Group MYSQL_FETCH_ROW(3)