Hey, I was wondering how I could write a bash script which accepts:
cat <<% | bash ./results06
----------------------------------------------------------
Exam Results 2006
----------------------------------------------------------
... (1 Reply)
hi, i'm trying to write a script to check if the home directories of users are set correctly. below is an extract of the script
here, i am trying to put the name of the owner of the home directory into the variable dirperm (by reading lines in /etc/passwd). however, it seems that when the... (1 Reply)
Hi folks,
I need to write a script that should activate a process according to the current hour.
The process should be activatet only if the hour is between midnight (00:00) and 07:00.
How should I create the condition?
Thanks in advance,
Nir (2 Replies)
How to validate the first line from 1-8 position of audit file that contains the script run date... script could run in random dates.
head -1 file1
20090516 100034837SHDHSHE (9 Replies)
Hi,
I have to validate the passwords for 100s of unix users across several servers. I have the list of unix users and servers with passwrods.
How can I check whether a password is correct or not using a single shell script?
Note : I do not have root privileges on any server. All the... (1 Reply)
hi there
I have file names in different format as below
triss_20111117_fxcb.csv
triss_fxcb_20111117.csv
xpnl_hypo_reu_miplvdone_11172011.csv
xpnl_hypo_reu_miplvdone_11-17-2011.csv
xpnl_hypo_reu_miplvdone_20111117.csv
xpnl_hypo_reu_miplvdone_20111117xfb.csv... (10 Replies)
Hi,
In a field, I should receive the date with time stamp in a particular field. But sometimes the vendor sends just the date or the timestamp or correctl the date×tamp. I have to figure out the the data is a date or time stamp or date×tamp.
If it is date then append "<space>00:00:00"... (1 Reply)
Hi Experts,
I am checking how to get day in Perl.
If it is “Monday” I need to process…below is the pseudo code.
Can you please prove the code for below condition.
if (today=="Monday" )
{
while (current_time LESS THAN 9:01 AM)
... (1 Reply)
hello,
in a file exist entries in date format YYYYMMDD. i want to find out, if there are dates, which isn't today's date.
file:
date example text
20140714 <= not today's date
20140715 <= not today's date
20140716 <= today's date
my idea is to use Perderabo's datecalc
... (2 Replies)
so i have scripts that get run in ways similar to this:
cat script.pl | perl - $1 $2 $3
cat script.rb | ruby - $1 $ 2 $3
my question is, how can i verify that that the "perl" or "ruby" or "python" tool being run on the box is actually a legit tool? meaning, someone may move the tool from... (2 Replies)
Discussion started by: SkySmart
2 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)