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Top Forums Shell Programming and Scripting How to preserve spaces in input fields with awk? Post 302872491 by Armoric on Friday 8th of November 2013 01:17:30 PM
Old 11-08-2013
Ok to use the printf but I still have to use the echo command so I assume it will still remove the spaces no ?

---------- Post updated at 01:16 PM ---------- Previous update was at 12:44 PM ----------

Quote:
Originally Posted by RudiC
Putting the quotes at the right places will make it work:
Code:
cat file | while read l_line; do echo "$(echo "$l_line" | awk -F',' '{OFS = ",";$1=""; print $0}')"; done
,item,      12345678
,item,      12345678
,item,      12345678

mmmhh yeah it does the trick. Don't know what I did wrong at the first place because I tried to do the same but I probably put the quotes badly.
Thanks for this simple workaround !

---------- Post updated at 01:17 PM ---------- Previous update was at 01:16 PM ----------

Quote:
Originally Posted by shamrock
Try the awk script below...
Code:
awk -F"[ ]" '{s="";n=split($1,a,",");for(i=2;i<=n;i++) s = s ? s","a[i] : ","a[i];$1=s;print}' file

Thanks Shamrock it's a nice piece of code. I assume it's more powerfull to use such a syntax so maybe I'll integrate it into my script.
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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