Sponsored Content
Top Forums Shell Programming and Scripting How do I take out(remove) the date part in the file name in a script? Post 302871799 by Don Cragun on Thursday 7th of November 2013 01:55:46 AM
Old 11-07-2013
Do not post classroom or homework problems in the main forums. Homework and coursework questions can only be posted in this forum under special homework rules.

Please review the rules, which you agreed to when you registered, if you have not already done so.

More-than-likely, posting homework in the main forums has resulting in a forum infraction. If you did not post homework, please explain the company you work for and the nature of the problem you are working on.

If you did post homework in the main forums, please review the guidelines for posting homework and repost.

Thank You.

The UNIX and Linux Forums.
 

10 More Discussions You Might Find Interesting

1. HP-UX

How do I take out(remove) the date part in the file name?

Hi Guys here I am again, I have two files in a specified location. Location ex: /opt/xdm/input/ input file names: 1. abc_app.yyyymmdd.dtd 2. abd_app.yyyymmdd.dtd I need to build a code that reads the files from the location based on the oldest date and cuts the date part... (5 Replies)
Discussion started by: ruthless
5 Replies

2. Shell Programming and Scripting

remove certain part of file name

Hi, Is it possible to remove the first part of the file name using find. i.e i have something like 2006abc.txt , 1007bed.txt etc, I wanna rename them to abc.txt , bed.txt I tried some stupid way.. find . -name '*.txt' -exec mv {} `cut -f2-5 -d"_" {}` \; somehow iam not getting it. ... (3 Replies)
Discussion started by: braindrain
3 Replies

3. Shell Programming and Scripting

Remove part of the file

I have an xml file, from where I need to take out Application2 entries and keep the others. I need to remove from <product> to </product> and the key element to look for while removing should be <application> as other pairs can be same for others. <product> ... (10 Replies)
Discussion started by: chiru_h
10 Replies

4. Shell Programming and Scripting

Remove part of a column in a text file

I have a text file with delimiter "|" and sometimes the zipcode is in "5th" column or "6th" column. I want to scan the file and remove the "-2323" from the zipcode which has zip+4 digits From blah|blah|foo|bar||blah|945523-232|USA blah|blah|foo|bar||blah|foo|94555-2323|USA To... (8 Replies)
Discussion started by: gubbu
8 Replies

5. UNIX for Dummies Questions & Answers

Remove part of file name with sed & mv

Ok, so I have bunch of files that are named "orange__file_name.asm" and I want to batch rename them to "file_name.asm" I know that using "ls | sed s/orange__//" will get rid of the part of the file name I do not want. But how do I combine that with the mv command to actually do it? Thanks JG (5 Replies)
Discussion started by: john galt
5 Replies

6. UNIX for Dummies Questions & Answers

Remove part of file names in a directory

Hi, i have a directory full of pictures, .jpg files. Half of them begin with "beach_" (for ex beach_123_123456.jpg) i'm looking for a command to remove the "beach_" from all files in the directory. thanks (4 Replies)
Discussion started by: robertmanalio
4 Replies

7. Shell Programming and Scripting

Remove part of a file based on identifiers

here below is a part of the file cat fileName.txt NAME=APP-VA-va_mediaservices-113009-VA_MS_MEDIA_SERVER_NOT_PRESENT-S FIXED=false DATE= 2013-02-19 03:46:04.4 PRIORITY=HIGH RESOURCE NAME=ccm113 NAME=APP-DS-ds_ha-140020-databaseReplicationFailure-S FIXED=false DATE= 2013-02-19... (4 Replies)
Discussion started by: vivek d r
4 Replies

8. Shell Programming and Scripting

How to remove the date part of the file?

Hi Gurus, I have file name like: abcd.20131005.dat I need to remove mid part of data final name should be abcd.dat thanks in advance (2 Replies)
Discussion started by: ken6503
2 Replies

9. Shell Programming and Scripting

Please help, need to create script to remove lines by date in file

Please Help (novice to PERL and SHELL scripting)…. Need to create a script which removes all lines in $filename = "cycle_calendar_ftp_out" older than current date – a variable which will be a number of days passed to script. For Ex it will look at the end date which is the last field (4) and... (2 Replies)
Discussion started by: m3pwr
2 Replies

10. Shell Programming and Scripting

Remove part of the file using a condition

Gents, Is there the chance to remove part of the file, Taking in consideration this condition. For each record the first row start with the string % VE should be 56 rows for each records.. first row = % VE last row = % sw total 56 rows for each record. Then in the case that the... (4 Replies)
Discussion started by: jiam912
4 Replies
httppower(8)							     powerman							      httppower(8)

NAME
httppower - communicate with HTTP based power distribution units SYNOPSIS
httppower [--url URL] DESCRIPTION
httppower is a helper program for powerman which enables it to communicate with HTTP based power distribution units. It is run interac- tively by the powerman daemon. OPTIONS
-u, --url URL Set the base URL. INTERACTIVE COMMANDS
The following commands are accepted at the httppower> prompt: auth user:pass Authenticate to the base URL with specified user and password, using ``basic'' HTTP authentication which sends the user and password over the network in plain text. seturl URL Set the base URL. Overrides the command line option. get [URL-suffix] Send an HTTP GET to the base URL with the optional URL-suffix appended. post [URL-suffix] key=val[&key=val]... Send an HTTP POST to the base URL with the optional URL-suffix appended, and key-value pairs as argument. FILES
/usr/sbin/httppower /etc/powerman/powerman.conf ORIGIN
PowerMan was originally developed by Andrew Uselton on LLNL's Linux clusters. This software is open source and distributed under the terms of the GNU GPL. SEE ALSO
powerman(1), powermand(8), httppower(8), plmpower(8), vpcd(8), powerman.conf(5), powerman.dev(5), powerman-devices(7). http://sourceforge.net/projects/powerman powerman-2.3.5 2009-02-09 httppower(8)
All times are GMT -4. The time now is 01:18 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy