I have an Foxbase application that saves dates in a character field using a Unix date format.
Does anyone know what the formula is to convert back to a standard date, something that can be, I hesitate to say, understood in a Windows environment, such as Excel or Access.
cheers
peter (2 Replies)
hi,
for reading a cobol indexed file i need to convert "mmddyy" date format to "ccyyddd" format.
i checked the datecalc and other scripts but couldnt modify them to cater to my need:(...
The datecalc gives an output which i believe is the total days till that date, but i want to convert it... (2 Replies)
HI,
Does anyone know how the alternative way to format date to 'Jul07' in UNIX-HP . I found HP Unix does not support date -d....:(
---------------------------------------------------------------
trxStartYear=2007
mthKey0=07
trxDay=20
key=`date -d ${trxStartYear}${mthKey0}${trxDay}... (2 Replies)
Hi , Can any one give me what is the date format for 3 character Month all caps (MON)
when I do date +%b it will give me Sep
But I want this to be SEP (all caps) .
Thanks in advance (1 Reply)
I have a comma delimited log file which has the date as MM/DD/YY in the 2nd column, and HH:MM:SS in the 3rd column.
I need to change the date format to YYYY-MM-DD and merge it with the the time HH:MM:SS. How will I got about this?
Sample input
02/27/09,23:52:31
02/27/09,23:52:52... (3 Replies)
I have a list of dates in the following format: mm/dd/yyyy and want to change these to the MySQL standard format: yyyy-mm-dd.
The dates in the original file may or may not be zero padded, so April is sometimes "04" and other times simply "4".
This is what I use to change the format:
sed -i '' -e... (2 Replies)
Hi Guys,
Need some help. I want to use the date command in Unix and having this below format as an output. the month should be in FIRST 3 LETTERS & ALL CAPS. And the DAY should be in two digits format
DESIRED OUTPUT:
09-JUN-11
I tried to use this command below but still it does... (2 Replies)
Hi All,
I'm new to forum good to hear all.
I stuck in converting date format in csv file using unix
csv file contains as below
,750,0000000000000000GCJR, ,06/22/2016 14:48:44
I want to convert into as below
,750,0000000000000000GCJR, ,06/22/2016 02:48:44 PM
Please reply asap..... (22 Replies)
i try to set linux date & time in specific format but it keep giving me error
Example :
date "+%d-%m-%C%y %H:%M:%S" -d "19-01-2017 00:05:01"
or
date +"%d-%m-%C%y %H:%M:%S" -d "19-01-2017 00:05:01"
keep giving me this error :
date: invalid date ‘19-01-2017 00:05:01'
Please use CODE tags... (7 Replies)
Discussion started by: umen
7 Replies
LEARN ABOUT PHP
datetime.format
DATETIME.FORMAT(3) 1 DATETIME.FORMAT(3)DateTime::format - Returns date formatted according to given format
Object oriented style
SYNOPSIS
public string DateTime::format (string $format)
DESCRIPTION
string DateTimeImmutable::format (string $format) string DateTimeInterface::format (string $format)
Procedural style
string date_format (DateTimeInterface $object, string $format)
Returns date formatted according to given format.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3)
o $format
- Format accepted by date(3).
RETURN VALUES
Returns the formatted date string on success or FALSE on failure.
EXAMPLES
Example #1
DateTime.format(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
echo $date->format('Y-m-d H:i:s');
?>
Procedural style
<?php
$date = date_create('2000-01-01');
echo date_format($date, 'Y-m-d H:i:s');
?>
The above example will output:
2000-01-01 00:00:00
NOTES
This method does not use locales. All output is in English.
SEE ALSO date(3).
PHP Documentation Group DATETIME.FORMAT(3)