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Homework and Emergencies Homework & Coursework Questions Help fixing my database script Post 302867163 by gamernerd101 on Wednesday 23rd of October 2013 02:35:59 PM
Old 10-23-2013
Help fixing my database script

1. The problem statement, all variables and given/known data:
I need help I get a variant of syntax errors when compiling my script to maintain a database. It's a simple database meant to create/view/maintain vehicles.


2. Relevant commands, code, scripts, algorithms:
my if statements have many syntax errors and I'm lost as to why. One key lines is line 8 my first if statement. Thanks in advance.


3. The attempts at a solution (include all code and scripts):
Code:
#! /bin/bash
# Automobile database

db=arg1
command=arg2
case $db in
    #create:
if [ -f "$db" ]; then
echo "DATABASE EXSISTS"

 if [ $arg3 != "" ]
 echo $arg3 > db

else
echo "Automobile Database" > db
echo "New database created"
fi
  esac

#add

read -p "Make of the car: " make

read -p "Model of the car: " model

read -p "Year of the car: " year

read -p "Color of the car: " color


if $year < 1870 || $year > 2020
echo "Error with $year"
fi
echo "$make, $model, $year, $color" >> db
echo "Successfully added a record to the database"

case $arg3:
 max=$( wc -l db )
 #all:
 cat db

 if $arg4 > $max
 echo "Error"
 fi
 sed -ne "1p;arg4p" db

#range:
if $arg4 > $max || $arg5 > $max || $arg4 > $arg5
error
fi
sed -ne "1p;arg4,arg5p" $db
esac



#delete:
        case $arg3:
        max=$( wc -l db )
      sed -ie '2,$d' db
     single:
     if $arg4 > $max
     echo "error"
     fi

     sed -ie "$arg4d" db


     range:
     if $arg4 > $max || $arg5 > $max || $arg4 > $arg5
           echo "Error"
           fi
     sed -ie "arg4,arg5d" db
esac


4. Complete Name of School (University), City (State), Country, Name of Professor, and Course Number (Link to Course):
NIU, dekalb il USA, Ege, CSCI 330

Note: Without school/professor/course information, you will be banned if you post here! You must complete the entire template (not just parts of it).
 

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INGRES_PCONNECT(3)							 1							INGRES_PCONNECT(3)

ingres_pconnect - Open a persistent connection to an Ingres database

SYNOPSIS
resource ingres_pconnect ([string $database], [string $username], [string $password], [array $options]) DESCRIPTION
Open a persistent connection to an Ingres database. There are only two differences between this function and ingres_connect(3): First, when connecting, the function will initially try to find a (persistent) link that is already opened with the same parameters. If one is found, an identifier for it will be returned instead of opening a new connection. Second, the connection to the Ingres server will not be closed when the execution of the script ends. Instead, the link will remain open for future use (ingres_close(3) will not close links established by ingres_pconnect(3)). This type of link is therefore called "persistent". PARAMETERS
o $database - The database name. Must follow the syntax: $[vnode::]dbname[/svr_class] o $username - The Ingres user name o $password - The password associated with $username o $options - See ingres_connect(3) for the list of options that can be passed RETURN VALUES
Returns an Ingres link resource on success or FALSE on failure SEE ALSO
ingres_connect(3), ingres_close(3). PHP Documentation Group INGRES_PCONNECT(3)
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