Thanks for your replies guys

Below is a simple perl code . . Check it out . .

Code:

 
#! usr/bin/perl
use POSIX;
use strict;
use warnings;
my $file = $ARGV[0];
open FILE,'<', $file;
while (my $line = <FILE>){print $line;}
my $var = 5;
print $var;

it gave me

Code:

 
0.355u 1.00s 0:1.01 110.2% 0+0k 0+0io 0pf+0w

on the terminal, after printing the contents of the file that I've given as ARGV[0] . .
And yes, that file does not contain the above line . .

uname -a gives,

Code:

 
Linux <username> 2.6.18-274.3.1.el5 #1 SMP <date & time> x86_64 GNU/Linux

I am using Redhat 5.0 . .

Also, time sleep 10 gives,

Code:

 
0.000u 0.000s 0:10.00 0.0% 0+0k 0+0io 0pf+0w

so I guess you're on right track, Corona688

So, What does the rest four fields signify?

Thanks,
-MD