How can I use the value of an argument as a filename? Example:
The argument for a process is 999. I would like the output of the process to be placed in a file called 999. I have tried using $$1, but that only assigns a unigue number.
thanks
JP (1 Reply)
Hi,
Can someone please explain to me how I can get a function to recognize a file given as an argument to a script.
Suppose the script has the argument as follows:
sh script file
and the function is as follows:
function display_file () {
cat $1
}
and it s then called
#main program... (1 Reply)
If I run the following command remotely after ssh than it works fine
su - oracle -c "/oracle/product/102/db/bin/dbshut"
But If I run the following command it doesn't work
su - oracle -c "/oracle/product/102/db/bin/lsnrctl stop"
Because I think there is a space is present between lsnrctl and... (1 Reply)
How can I pass $var_find variable as argment to find command?
test.sh
var_find=' \( -name "*.xml" -o -name "*.jsp" \) '
echo "${var_find}"
find . -type f ${var_find} -print
# Below statement works fine.. I want to replace this with the above..
#find . \( -name "*.xml" -o -name... (4 Replies)
Hi,
I need to pass the argument in my shell script as db_ubackup20111015*.log
Scenario:
I have backup log file location in /home/backup directory (more than 40 days). I need to check the log file of the latest one (tail .
a. How I can retrieve the latest value other than passing... (1 Reply)
Can someone let me know how could I achieve this
In one of per script I am calling the shell script but I need to so one thing that is one shell script call I need to pass pne argument.In below code I am calling my ftp script but here I want to pass one argument so how could I do this (e.g:... (5 Replies)
I need to write a shell script, when I run that script I should pass those arguments if not, then script should not run and pass the error message like
invalid option - - should pass the argument.
and Exit from the script
https://www.unix.com/images/misc/progress.gif (1 Reply)
I need to write a shell script, when I run that script I should pass those arguments if not, then script should not run and pass the error message like
invalid option - - should pass the argument.
and Exit from the script (8 Replies)
Hi all,
$ echo $SHELL
/bin/bash
Requirement - How to pass oracle sql script as argument to unix shell script?
$ ./output.sh users.sql
Below are the shell scripts and the oracle sql file in the same folder.
Shell Script
$ cat output.sh
#!/bin/bash
.... (7 Replies)
I'm looking to write a script that takes a .txt filename as an argument, reads the file line by line, and passes each line to a command. For example, it runs command --option "LINE 1", then command --option "LINE 2", etc. I am fetching object files from a library file, I have all the object file... (2 Replies)
Discussion started by: Paul Martins
2 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)