10-16-2013
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Man pages....look at the man pages. If you don't have them, you can find them on-line. Read them when you have nothing better to do. Find new commands and new ways of doing things.
The answer:
The only way to direct the standard output and standard
error separately is by invoking... (0 Replies)
Discussion started by: thehoghunter
0 Replies
2. Shell Programming and Scripting
Hi everyone,
Simple scripting question here. I have:
#!/bin/csh
if ( -e $HOME/*.core) then
rm -f $HOME/*.core >& /dev/null
else
echo "No core files to delete."
endif
But I keep getting the /home/user/*.core: no match
dialog. How can I suppress this? or, why is... (0 Replies)
Discussion started by: jolok
0 Replies
3. Shell Programming and Scripting
Here is my script
#!/bin/bash
pwd
cd /var/lib/pgsql
Both "pwd" and "cd" are not executed is there any other way i can change the current working directory to /var/lib/pgsql pls help! (9 Replies)
Discussion started by: perk_bud
9 Replies
4. UNIX for Dummies Questions & Answers
Portion of my script below :
if ; then
NUMBEROFFEILDS=`cat ${BASE_SCRIPT_LOC}/standardfilecleanup.lst|grep -w ${db_file_path}|awk -F: '{print NF}'`
COUNT=4
while ; do
awk_var="$"`echo $COUNT`
file_name1=`cat ${BASE_SCRIPT_LOC}/standardfilecleanup.lst|grep -w... (1 Reply)
Discussion started by: findprakash
1 Replies
5. UNIX for Dummies Questions & Answers
I am using perl to perform a search and replace. It works at the command line, but not in the csh shell script
perl -pi -e 's@/Pattern@@g' $path/$file
I used the @ as my delimiter because the pattern contains "/" (3 Replies)
Discussion started by: NobluesFDT
3 Replies
6. Shell Programming and Scripting
I have a csh script which I am using to run a program
set data = $argv
set inmod = $argv
set nxz = $argv
# Remove the file extension .pmod
set data = ` echo $data | awk 'BEGIN { FS=".dat" } { print $1 }' `
set inmod = ` echo $inmod | awk 'BEGIN { FS=".vmod" } { print... (8 Replies)
Discussion started by: kristinu
8 Replies
7. Shell Programming and Scripting
I need to count the number of lines in a .txt file and put it in a variable.
I am using the following code
#!/bin/bash
count = $(wc -l "some file.txt" | awk '{print$1}')
echo $count
It is giving the following error.
line3: count: command not foundWhat am I doing wrong here? :confused: (7 Replies)
Discussion started by: haritha.gorijav
7 Replies
8. Shell Programming and Scripting
cat tmp0.txt
700000
#!/bin/csh -fx
set id=`cat tmp0.txt`
echo $id
if ("$id" == "700000") then
echo "Good Morning"
endif
if ("$id" == "700002") then
echo "Good evening"
endif
My output from terminal
set id=`cat tmp0.txt`
cat tmp0.txt
echo 700000
700000
==... (9 Replies)
Discussion started by: vivien_chu
9 Replies
9. Shell Programming and Scripting
I have a simple script which will send a curl request and redirect the output to a log file.
for i in {1..20}
do
curl google.com -is >>log.log &
echo "request # $i" >> log.log
doneAfter it completes the execution, if I run the following command I should see 20 lines because I am printing... (4 Replies)
Discussion started by: heykiran
4 Replies
10. Shell Programming and Scripting
i have strange behavior i have csh file that run java process something like this :
run_server.csh
#!/usr/bin/tcsh
java -Dtest=testparam -cp ${TEST}/lib/device.jar:${TEST}/conf:${TEST}/lib/commons-logging-1.1.1.jar com.device.server
when i run it like this :... (7 Replies)
Discussion started by: umen
7 Replies