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Top Forums Shell Programming and Scripting Search string within a file and list common words from the line having the search string Post 302863711 by RavinderSingh13 on Tuesday 15th of October 2013 04:02:20 AM
Old 10-15-2013
Quote:
Hi R Singh,

Thanks for your reply. I missed mentioning one info that is the values after "name=" are not static/fixed but can change/dynamic. I used ABCD/PQRS/XYZ as examples only.

Its like extracting the string after "name=" for all lines having "human" and then count the total occurances for each value of "name="
royzlifeHi R Singh,

Thanks for your reply. I missed mentioning one info that is the values after "name=" are not static/fixed but can change/dynamic. I used ABCD/PQRS/XYZ as examples only.

Its like extracting the string after "name=" for all lines having "human" and then count the total occurances for each value of "name="

Hello,

here is script solution for same.

Code:
> Output_latest
k=0
null=`echo ""`
count_human=0
count=0
zero=0

while read line
do
count=0
check_human=`echo $line | grep "human" | grep -v '^$`
name_check=`echo $line | grep "name" | grep -v '^$'`
set -A value_name_check
value_name_check=`echo $name_check | awk -F"=" '{print$2}' | grep -v '^$' | cut -f1 -d.`

                while read line1
                do
                check_count=`echo $line1 | grep -v '^$' |  grep "$value_name_check".`
                                if [[ -n ${check_count} ]]
                                then
                                let "count = count + 1"
                                fi

                done < "requirement_check_count"
                if [[ -n ${check_human} ]]
                then
                let "count_human = count_human + 1"
                fi
        if [[ "$value_name_check" != "$null" ]]
        then
        echo "Count for" $value_name_check "is" $count >> Output_latest
        fi
done < "requirement_check_count"
echo "Count for human is=" $count_human
 

awk '!x[$0]++' Output_latest


Output will be as follows.


Code:
$ ksh check_requirement_check_count1.ksh
Count for human is= 4
Count for ABCD is 2
Count for PQRS is 1
Count for XYZ is 1


Thanks,
R. Singh
 

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DWWW-FIND(8)							      Debian							      DWWW-FIND(8)

NAME
dwww-find - find documentation related to a search argument SYNOPSIS
dwww-find [--program|--menu|--documentation|--docfile|--doc-base-list] [--skip=number] argument [...] DESCRIPTION
dwww-find is part of the dwww package, which provides access to on-line documentation on a Debian system via WWW. dwww-find searches for a documentation related to a given program, for entries from Debian Documentation Menu, or at least for documents registered with doc-base. It returns a HTML-formatted document with search results. OPTIONS
--program Search for documentation (man pages, info files, etc.) related to program specified by argument. --menu Search for entries in Debian Documentation Menu pages generated by dwww-build-menu(8). --documentation Search in documentation files registered with doc-base. It uses search++(1) for searching. --docfile Search for documentation for package, which contains the file specified by the argument. The file must be located in or below a directory that has been allowed by the system administrator; see dwww(7) for more info. --doc-base-list Show list of registerered doc-base files for given argument, which should be specified as format/document-id, where document-id is an identificator of registered doc-base document, and format is a name of format (e.g. text or pdf) registered by the document, for which the list list is to be generated. --skip=number Works only with --documentation. Skip number of search results. When no options are specified, --program is assumed. FILES
/etc/dwww/dwww.conf Configuration file for dwww. SEE ALSO
dwww(7), dwww-quickfind(8), dwww-build-menu(8), dwww-index++(8), search++(1), Debian doc-base Manual in /usr/share/doc/doc-base/doc-base.html/index.html. AUTHORS
Lars Wirzenius. Robert Luberda. See dwww(7) for copyrights and stuff. dwww 1.11.4 January 15th, 2011 DWWW-FIND(8)
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