sorry for the goofup .. but being fairly new .. i am not sure of the exact version .. when i do a echo $0 , i just get 'ksh' without any version with it .. and a uname -r returns '5.10'
Request your help on decoding this. Thanks
That would indicate Solaris 10. The ksh93 version is not recent enough to support %T (and the underlying date system does not support "ago", for example)..
Your best bet may be to use perl . For example:
to print the date 3 days ago in your current locale.
This User Gave Thanks to Scrutinizer For This Post:
Hi i am trying to subtract days from current date. For example todays date is 10/03/2006. If i subtract 2 days it should give 8/03/2006. I am also trying to find the access date of a file in dd/mm/yyyy format. Can any one please help in how to do this.
Ramesh (1 Reply)
how can we add or subtract days from the output of date command in unix...
like if i want to subtract a day from the result of date command like this..
v_date=`date +%Y%m%d`
this wud give me 20080519
now i want to subtract one day from this.. so tht it wud give me 20080518..
how do i do... (1 Reply)
hii all.
I have to get the date of the 7th day past from the current date.
if i give the current date as sep 3 then i must get the date as 27th of august.
can we get the values from the "cal" command.
cal | awk '{print $2}' will this type of command work.
actually my need is
if today is... (17 Replies)
Hi,
Anybody knows how to get what date was 28 days ago of the current system date through UNIX script.
Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010, (15 Replies)
Hi,
I'm writing an batch file to create report
In the batch file iam passing two arguments:startdate and finishdate
Ex: startdate=07-sep-2009 finishdate=07-sep-2011
I need to have script that takes command line argument as input and gives me out currentdate last year and current date... (2 Replies)
Hi i am writing a cron job.
so for it i need the 60 days old date form current date in variable.
Like today date is 27 jan 2011 then output value will be stote in variable in formet Nov 27.
i am using EST date, and tried lot of solution and see lot of post but it did not helpful for me. so... (3 Replies)
I am trying to find out the number of days between the current date and user defined date.
I took reference from here for the date2jd() function.
Modified the function according to my requirement. But its not working properly.
Original code from here is working fine.
#!/bin/sh... (1 Reply)
I have to display only those subscribers which are in "unconnected state" and the date is 90 days older than today's date.
Below command is used for this purpose:
cat vfsubscriber_20170817.csv | sed -e 's/^"//' -e '1d' | nawk -F '",' '{if ( (substr($11,2,4) == 2017) && ( substr($11,2,8) -lt... (1 Reply)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT CENTOS
lchage
lchage(1) General Commands Manual lchage(1)NAME
lchage - Display or change user password policy
SYNOPSIS
lchage [OPTION]... user
DESCRIPTION
Displays or allows changing password policy of user.
OPTIONS -d, --date=days
Set the date of last password change to days after Jan 1 1970.
Set days to -1 to disable password expiration (i.e. to ignore --mindays, and --maxdays and related settings).
Set days to 0 to enforce password change on next login. (This also disables password expiration until the password is changed.)
-E, --expire=days
Set the account expiration date to days after Jan 1 1970. Set days to -1 to disable account expiration.
-i, --interactive
Ask all questions when connecting to the user database, even if default answers are set up in libuser configuration.
-I, --inactive=days
Disable the account after days after password expires (after the user is required to change the password). Set days to -1 to keep
the account enabled indefinitely after password expiration.
-l, --list
Only list current user's policy and make no changes.
-m, --mindays=days
Require at least days days between password changes. Set days to 0 or -1 to disable this requirement.
If this value is larger than the value set by --maxdays, the user cannot change the pasword.
-M, --maxdays=days
Require changing the password after days since last password change. Set days to -1 to disable password expiration.
-W, --warndays=days
Start warning the user days before password expires (before the user is required to change the password). Set days to 0 or -1 to
disable the warning.
EXIT STATUS
The exit status is 0 on success, nonzero on error.
NOTES
Note that "account expiration" (set by --expire) is distinct from "password expiration" (set by --maxdays). Account expiration happens on
a fixed date regardless of password changes. Password expiration is relative to the date of last password change.
libuser Nov 8 2012 lchage(1)