[Solved] Grep in bash script Post: 302863327

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Top Forums UNIX for Dummies Questions & Answers [Solved] Grep in bash script Post 302863327 by parpaa on Sunday 13th of October 2013 11:43:42 PM

10-14-2013

Registered User

[Solved] Grep in bash script

Hi Experts,

I'm writing script to find out last files and its modified date - unfortunately am having problem with the below script.

Error message:

Code:

"grep: sales.txt: No such file or directory"

Code:

#!/bin/bash
var=1
var1=`awk '{n++} END {print n}' sales.txt`

while [[ ${var} -le  ${var1} ]]
do


prod=$var
member=`grep ^$prod, sales.txt | cut -d "," -f2 | tr -d "\15"`

due1=`grep ^$prod, sales.txt | tail -1 | cut -d "," -f3 | tr -d "\15"`
FTP=`grep ^$prod, sales.txt | tail -1 | cut -d "," -f4 | tr -d "\15"`
FolderName=`grep ^$prod, sales.txt | tail -1 | cut -d "," -f5 | tr -d "\15"`
curdate=`date +%Y-%m-%d`
duedate1=$( date +%Y-%m-$due1 )
keyword=`grep ^$prod, sales.txt | tail -1 | cut -d "," -f7 | tr -d "\15"`
#echo "$member","$due1","$FolderName","$keyword","$FTP"

if [[ "$FTP" == "ABC" ]]
then

echo $FolderName
cd /
cd /archive/$FolderName
file1_To_Copy=`ls -tr *"$keyword"* |tail -n 1`
last_mod_date1=`ls --time-style=+%Y-%m-%d -ld $file1_To_Copy | awk '{print $6}'`

else
echo "do nothing"
fi
echo "$member","$due1","$FolderName","$keyword","$FTP","$file_To_Copy","$last_mod_date1"

var=`expr $var + 1`

done

Any help is greatly appreciated
thank you

Last edited by parpaa; 10-14-2013 at 12:51 AM..

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