Sponsored Content
Top Forums UNIX for Dummies Questions & Answers Subtracting number of days from current date Post 302862747 by dev.devil.1983 on Friday 11th of October 2013 11:45:25 AM
Old 10-11-2013
This isnt working, isnt returning anything
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

subtracting a days from current date

Hi i am trying to subtract days from current date. For example todays date is 10/03/2006. If i subtract 2 days it should give 8/03/2006. I am also trying to find the access date of a file in dd/mm/yyyy format. Can any one please help in how to do this. Ramesh (1 Reply)
Discussion started by: rameshspal
1 Replies

2. UNIX for Dummies Questions & Answers

adding or subtracting days in the o/p of date

how can we add or subtract days from the output of date command in unix... like if i want to subtract a day from the result of date command like this.. v_date=`date +%Y%m%d` this wud give me 20080519 now i want to subtract one day from this.. so tht it wud give me 20080518.. how do i do... (1 Reply)
Discussion started by: St.Fartatric
1 Replies

3. Shell Programming and Scripting

How to find a date which is 7 days past when given current date

hii all. I have to get the date of the 7th day past from the current date. if i give the current date as sep 3 then i must get the date as 27th of august. can we get the values from the "cal" command. cal | awk '{print $2}' will this type of command work. actually my need is if today is... (17 Replies)
Discussion started by: ladtony
17 Replies

4. Shell Programming and Scripting

how to get what date was 28 days ago of the current system date IN UNIX

Hi, Anybody knows how to get what date was 28 days ago of the current system date through UNIX script. Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010, (15 Replies)
Discussion started by: kandi.reddy
15 Replies

5. Shell Programming and Scripting

Date after 5 days from current date in YYYYMMDD format

Hello Experts, How do i get date after 5 days from current date in YYYYMMDD format? How do you compare date in YYYYMMDD format? Thanks (8 Replies)
Discussion started by: needyourhelp10
8 Replies

6. Windows & DOS: Issues & Discussions

Adding or subtracting days from current date in batch script

Hi, I'm writing an batch file to create report In the batch file iam passing two arguments:startdate and finishdate Ex: startdate=07-sep-2009 finishdate=07-sep-2011 I need to have script that takes command line argument as input and gives me out currentdate last year and current date... (2 Replies)
Discussion started by: anand1773
2 Replies

7. Shell Programming and Scripting

How to Get 60 days Old date from current date in KSH script

Hi i am writing a cron job. so for it i need the 60 days old date form current date in variable. Like today date is 27 jan 2011 then output value will be stote in variable in formet Nov 27. i am using EST date, and tried lot of solution and see lot of post but it did not helpful for me. so... (3 Replies)
Discussion started by: Himanshu_soni
3 Replies

8. Shell Programming and Scripting

Number of days between the current date and user defined date

I am trying to find out the number of days between the current date and user defined date. I took reference from here for the date2jd() function. Modified the function according to my requirement. But its not working properly. Original code from here is working fine. #!/bin/sh... (1 Reply)
Discussion started by: hiten.r.chauhan
1 Replies

9. UNIX for Beginners Questions & Answers

Subscribers with Date 90 days older than current date

I have to display only those subscribers which are in "unconnected state" and the date is 90 days older than today's date. Below command is used for this purpose: cat vfsubscriber_20170817.csv | sed -e 's/^"//' -e '1d' | nawk -F '",' '{if ( (substr($11,2,4) == 2017) && ( substr($11,2,8) -lt... (1 Reply)
Discussion started by: dia
1 Replies

10. HP-UX

awk command in hp UNIX subtract 30 days automatically from current date without date illegal option

current date command runs well awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat subtract 30 days fails awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
PERLHACKTUT(1)						 Perl Programmers Reference Guide					    PERLHACKTUT(1)

NAME
perlhacktut - Walk through the creation of a simple C code patch DESCRIPTION
This document takes you through a simple patch example. If you haven't read perlhack yet, go do that first! You might also want to read through perlsource too. Once you're done here, check out perlhacktips next. EXAMPLE OF A SIMPLE PATCH
Let's take a simple patch from start to finish. Here's something Larry suggested: if a "U" is the first active format during a "pack", (for example, "pack "U3C8", @stuff") then the resulting string should be treated as UTF-8 encoded. If you are working with a git clone of the Perl repository, you will want to create a branch for your changes. This will make creating a proper patch much simpler. See the perlgit for details on how to do this. Writing the patch How do we prepare to fix this up? First we locate the code in question - the "pack" happens at runtime, so it's going to be in one of the pp files. Sure enough, "pp_pack" is in pp.c. Since we're going to be altering this file, let's copy it to pp.c~. [Well, it was in pp.c when this tutorial was written. It has now been split off with "pp_unpack" to its own file, pp_pack.c] Now let's look over "pp_pack": we take a pattern into "pat", and then loop over the pattern, taking each format character in turn into "datum_type". Then for each possible format character, we swallow up the other arguments in the pattern (a field width, an asterisk, and so on) and convert the next chunk input into the specified format, adding it onto the output SV "cat". How do we know if the "U" is the first format in the "pat"? Well, if we have a pointer to the start of "pat" then, if we see a "U" we can test whether we're still at the start of the string. So, here's where "pat" is set up: STRLEN fromlen; char *pat = SvPVx(*++MARK, fromlen); char *patend = pat + fromlen; I32 len; I32 datumtype; SV *fromstr; We'll have another string pointer in there: STRLEN fromlen; char *pat = SvPVx(*++MARK, fromlen); char *patend = pat + fromlen; + char *patcopy; I32 len; I32 datumtype; SV *fromstr; And just before we start the loop, we'll set "patcopy" to be the start of "pat": items = SP - MARK; MARK++; sv_setpvn(cat, "", 0); + patcopy = pat; while (pat < patend) { Now if we see a "U" which was at the start of the string, we turn on the "UTF8" flag for the output SV, "cat": + if (datumtype == 'U' && pat==patcopy+1) + SvUTF8_on(cat); if (datumtype == '#') { while (pat < patend && *pat != ' ') pat++; Remember that it has to be "patcopy+1" because the first character of the string is the "U" which has been swallowed into "datumtype!" Oops, we forgot one thing: what if there are spaces at the start of the pattern? "pack(" U*", @stuff)" will have "U" as the first active character, even though it's not the first thing in the pattern. In this case, we have to advance "patcopy" along with "pat" when we see spaces: if (isSPACE(datumtype)) continue; needs to become if (isSPACE(datumtype)) { patcopy++; continue; } OK. That's the C part done. Now we must do two additional things before this patch is ready to go: we've changed the behaviour of Perl, and so we must document that change. We must also provide some more regression tests to make sure our patch works and doesn't create a bug somewhere else along the line. Testing the patch The regression tests for each operator live in t/op/, and so we make a copy of t/op/pack.t to t/op/pack.t~. Now we can add our tests to the end. First, we'll test that the "U" does indeed create Unicode strings. t/op/pack.t has a sensible ok() function, but if it didn't we could use the one from t/test.pl. require './test.pl'; plan( tests => 159 ); so instead of this: print 'not ' unless "1.20.300.4000" eq sprintf "%vd", pack("U*",1,20,300,4000); print "ok $test "; $test++; we can write the more sensible (see Test::More for a full explanation of is() and other testing functions). is( "1.20.300.4000", sprintf "%vd", pack("U*",1,20,300,4000), "U* produces Unicode" ); Now we'll test that we got that space-at-the-beginning business right: is( "1.20.300.4000", sprintf "%vd", pack(" U*",1,20,300,4000), " with spaces at the beginning" ); And finally we'll test that we don't make Unicode strings if "U" is not the first active format: isnt( v1.20.300.4000, sprintf "%vd", pack("C0U*",1,20,300,4000), "U* not first isn't Unicode" ); Mustn't forget to change the number of tests which appears at the top, or else the automated tester will get confused. This will either look like this: print "1..156 "; or this: plan( tests => 156 ); We now compile up Perl, and run it through the test suite. Our new tests pass, hooray! Documenting the patch Finally, the documentation. The job is never done until the paperwork is over, so let's describe the change we've just made. The relevant place is pod/perlfunc.pod; again, we make a copy, and then we'll insert this text in the description of "pack": =item * If the pattern begins with a C<U>, the resulting string will be treated as UTF-8-encoded Unicode. You can force UTF-8 encoding on in a string with an initial C<U0>, and the bytes that follow will be interpreted as Unicode characters. If you don't want this to happen, you can begin your pattern with C<C0> (or anything else) to force Perl not to UTF-8 encode your string, and then follow this with a C<U*> somewhere in your pattern. Submit See perlhack for details on how to submit this patch. AUTHOR
This document was originally written by Nathan Torkington, and is maintained by the perl5-porters mailing list. perl v5.18.2 2013-11-04 PERLHACKTUT(1)
All times are GMT -4. The time now is 12:23 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy