|
|
Sponsored Content
Top Forums
Shell Programming and Scripting
Assigning a value to a variable
Post 302862495 by erin00 on Thursday 10th of October 2013 10:32:03 PM
10-10-2013
|
|
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Another newbie to Unix scripting Q..
How do you assign a value resulting from a command, such as awk, to a variable.
I am currently trying:-
$awk '{print $1}' file1 > variable1
with no change to $variable1.
The line:
$awk '{print $1}' file1
does print the first line of the... (3 Replies)
Discussion started by: sirtrancealot
3 Replies
2. Shell Programming and Scripting
Hi
In my shell script, I'm trying to find the line count of a file and assign it to a variable.
LINE_COUNT=$(wc -l $FILE_NAME)
But when i display LINE_COUNT, i'm getting the linecount concatenated with the file name. I want only the number. How can i get the line count alone ? Someone... (2 Replies)
Discussion started by: janemary.a
2 Replies
3. Shell Programming and Scripting
hi all,
in ksh, how do i assign the output of a find command to a variable, e.g
am trying something like this :
totalNoFiles=$(print find ./ -name "SystemOut*.log");
but when i echo $totalNoFiles it displays
find ./ -name "SystemOut*.log"
instead of the total number of... (2 Replies)
Discussion started by: cesarNZ
2 Replies
4. Shell Programming and Scripting
can we make a global variable and store character values and add other values to that variable ?? for example
a="hello, John"
and can we add value ". How are you? so
a can have
"hello, John. How are you?"
can someone help me?? (2 Replies)
Discussion started by: bonosungho
2 Replies
5. Shell Programming and Scripting
Is there any difference between:
set variable=39 and variable=39 (1 Reply)
Discussion started by: proactiveaditya
1 Replies
6. Shell Programming and Scripting
Hi folks.
I have this variable called FirstIN that contains something like this: 001,002,003,004...
I am trying to assign the content of this variable into ModifiedIN but with the following format : 001 002 003 004...(changing the commas for spaces)
I thought about using sed but i am not... (17 Replies)
Discussion started by: Stephan
17 Replies
7. Shell Programming and Scripting
my script is some thing like this
i11="{1,2,3,4,5,6,7,8,9,10,11,}"
echo "enter value"
read value ..............suppose i11
x="$value"
echo "$($value)" .............the echo should be {1,2,3,4,5,6,7,8,9,10,11,}
but its showing "i11" only.
plz help me out to get desired... (10 Replies)
Discussion started by: sagar_1986
10 Replies
8. Shell Programming and Scripting
Hi,
I have a list of files in a directory. Each file has a .txt and a .log extension i.e. file.txt & file.log, file1.txt & file1.log etc. The file with the .log extension may not always exist alongside the file with the .txt extension.
I need to copy the .txt file if there is a corresponding... (6 Replies)
Discussion started by: brunlea
6 Replies
9. Shell Programming and Scripting
Unable to get the value to a variable.
set -x
cd $HOME
echo "Enter the server name"
read a
echo $a
i=4
j=1
k = ps -ef | awk '/server1/{ print $4 }' | tail -$i | head -$j`
echo $k
When I do the same in command line it works, however the same does not work when I provide that in the... (1 Reply)
Discussion started by: venkidhadha
1 Replies
10. Shell Programming and Scripting
I have a date column as 06302015 but I need to have variable which extracts 063015.
Am trying something like below but it is not assigning
Please let me know if am missing something. Thanks in advance.
################################
#!/usr/bin/ksh
DT=06302015
... (7 Replies)
Discussion started by: weknowd
7 Replies
LEARN ABOUT SUSE
grep-changelog
grep-changelog(1) General Commands Manual grep-changelog(1) NAME
grep-changelog - print ChangeLog entries matching criteria SYNOPSIS
grep-changelog [options] [CHANGELOG...] DESCRIPTION
grep-changelog searches the named CHANGELOGs (by default files matching the regular expressions ChangeLog and ChangeLog.[0-9]+) for entries matching the specified criteria. At least one option or file must be specified. This program is distributed with GNU Emacs. OPTIONS
The program accepts unambiguous abbreviations for option names. --author=AUTHOR Print entries whose author matches regular expression AUTHOR. --text=TEXT Print entries whose text matches regular expression TEXT. --exclude=TEXT Exclude entries matching regular expression TEXT. --from-date=YYYY-MM-DD Only consider entries made on or after the given date. ChangeLog date entries not in the "YYYY-MM-DD" format are never matched. --to-date=YYYY-MM-DD Only consider entries made on or before the given date. --rcs-log Print output in a format suitable for RCS log entries. This format removes author lines, leading spaces, and file names. --with-date In RCS log format, print short dates. --reverse Show matches in reverse order. --version Display version information. --help Display basic usage information. COPYING
Copyright (C) 2008, 2009 Free Software Foundation, Inc. Permission is granted to make and distribute verbatim copies of this document provided the copyright notice and this permission notice are preserved on all copies. Permission is granted to copy and distribute modified versions of this document under the conditions for verbatim copying, provided that the entire resulting derived work is distributed under the terms of a permission notice identical to this one. Permission is granted to copy and distribute translations of this document into another language, under the above conditions for modified versions, except that this permission notice may be stated in a translation approved by the Free Software Foundation. grep-changelog(1)