Sponsored Content
Top Forums Shell Programming and Scripting Incrementing parts of ten digits number by parts Post 302862479 by Natalie on Thursday 10th of October 2013 09:32:21 PM
Old 10-10-2013
I got the idea, thanks. You helped me a lot. But my last numbers goes only until 09 and then it starts from 02 again. Why? it does not reach even 100 for incrementing days or months.... Sorry just I try to do my best to fix code but I am not good at programming I guess....

Code:
if [ -f "kuku.txt" ]
     then

n=$(sort /Users/Natalie/1/kuku.txt | tail -1)
fourthoct=${n:0:4}
thirdoct=${n:4:2}
secondoct=${n:6:2}
firstoct=${n:8:2}

  wardevent=$(expr $firstoct + 0);
  if [ ! $((++wardevent)) -eq 100 ]
                 then
                      data="0$wardevent"
                  else
                    firstoct=0
                    data="0$firstoct"
                   if [ $((++secondoct)) -eq 32 ]
                         then
                        secondoct=0
                         if [ $((++thirdoct)) -eq 13 ]
                               then
                                thirdoct=0
                                   ((++fourthoct))

fi
fi
fi

printf  $fourthoct$thirdoct$secondoct$data > '/Users/Natalie/1/kuku.txt'
      else
echo ` date +%Y%m%d`"00" >'/Users/Natalie/1/kuku.txt'
fi


Last edited by Natalie; 10-10-2013 at 11:07 PM..
 

9 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

cksum parts of a file

Every time we build an executable the date and time are put into the file, I need to run checksum on just the working lines.(IE, no header files) Is this even possible, if so how would I go about it? I am using a HP-UX server any help you can give me will be greatly appreciated. Thanks (6 Replies)
Discussion started by: crazykelso
6 Replies

2. Shell Programming and Scripting

getting parts of a file

Hello, I'm trying to retreive certain bits of info from a file. the file contains a list like this info1:info2:info3:info4 info1:info2:info3:info4 info1:info2:info3:info4 info1:info2:info3:info4 how do i pick out only info2 or only info3 without the others? Thanks (11 Replies)
Discussion started by: bebop1111116
11 Replies

3. Shell Programming and Scripting

Extracting parts of a file.

Hello, I have a XML file as below and i would like to extract all the lines between <JOB & </JOB> for every such occurance. The number of lines between them is not fixed. Anyways to do this awk? ============ <JOB APR="1" AUG="1" DEC="1" FEB="1" JAN="1" JUL="1" JUN="1" MAR="1" MAY="1"... (3 Replies)
Discussion started by: srivat79
3 Replies

4. Shell Programming and Scripting

[ask]break line number into several parts

hlow all, i have file with wc -l file.txt is 3412112 line number so I want to break these files into several parts with assumsi line 1-1000000 will be create part1.txt and 1000001-2000000 will create part2.txt and 2000001-3000000 will create part3.txt and 3000001-3412112 will create... (5 Replies)
Discussion started by: zvtral
5 Replies

5. Shell Programming and Scripting

Parts is parts, but all together ...

I understand the individual pieces of the following (with one exception ..), but how does it all work as one? find ${HOME}/reports/ -name surveyresult*.txt -exec ls -1 {} \; | /usr/xpg4/bin/grep -E \ "${HOME}/reports/surveyresult{14,14}.txt" | sort > ${ResultsFileList} Find all files like... (1 Reply)
Discussion started by: jdorn001
1 Replies

6. Shell Programming and Scripting

Extract Parts of File

Hello All, I have a file like this Define schema flat_file_schema ( a varchar(20) ,b varchar(30) ,c varchar(40) ); (Insert into table ( a ,b ,c ) values ( 1 ,2 ,3 ); (4 Replies)
Discussion started by: nnani
4 Replies

7. Shell Programming and Scripting

Combine two parts of a file

Hello All, I have a file like this APPLY ( 'INSERT INTO brdcst_media_cntnt ( cntnt_id ,brdcst_media_cntnt_cd ,cntnt_prvdr_cd ,data_src_type_cd ,cntnt_titl_nm ,cntnt_desc ,batch_dt ,batch_id ) VALUES ( :cntnt_id (3 Replies)
Discussion started by: nnani
3 Replies

8. Shell Programming and Scripting

Getting various parts from the log

I am dealing with some app log, see example below: 22:16:13.601 ClientSession(905)--Connection(5)--SELECT GETDATE() 22:16:13.632 ClientSession(158)--Connection(5)--SELECT 1 22:16:13.632 ClientSession(848)--Connection(6735)--SELECT 1 So far I needed to collect certain column from it, such as... (3 Replies)
Discussion started by: migurus
3 Replies

9. Shell Programming and Scripting

How to get first four parts of the string?

I have the string: XXXX.YYYY_ZZZ.20180724.01.txt I need to get rid of .txt and get full four parts XXXX.YYYY_ZZZ.20180724.01 I did: CTL=`echo XXXX.YYYY_ZZZ.20180724.01.txt | rev | cut -d"." -f4 | rev` But got only YYYY_ZZZ What should I do to get all four parts of that... (4 Replies)
Discussion started by: digioleg54
4 Replies
RDUP-UP(1)							       rdup								RDUP-UP(1)

NAME
rdup-up - update a directory tree with a rdup archive SYNOPSIS
rdup-up [OPTION]... DIRECTORY DESCRIPTION
With rdup-up you can update an (possibly) existing directory structure with a rdup archive. The rdup archive has to be given to rdup-up's standard input. Username and uids rdup outputs both the username and uid, the receiving system (which may be a totally different system) checks if the username and uid match. If the username and uid don't match the (numeric) uid is used on the file. The same holds true for the groupname and gid. OPTIONS
-n Do a dry-run and do not create anything on disk. -t Create DIRECTORY (ala mkdir -p) if it does not exist. -s N Strip N path components from a pathname. If the resulting pathname is empty after this operation it is skipped. Be careful however with the following structure: /foo /foo/bar /foo/bar/bla.txt /foo/blork/bla.txt With rdup-up -s2 this will leave: <empty> <empty> /bla.txt /bla.txt And the last 'bla.txt' will overwrite the previous one, this will happen without warnings. -r PATH This option is related to the -s option, but works different. The string PATH is removed from (the beginning of) each pathname. With -r /home/backup the pathname /home/backup/bin/mycmd becomes /bin/mycmd. The same could be done with -s 2, but then you need to count the slashes. Note -s is always performed before -r. -v Be more verbose and echo the processed files to standard output. -vv Be even more verbose and echo processed file and the uid and gid information to standard output. -T Show a table of contents of the rdup stream received (ala tar -tf -). With -T the directory argument is optional. -T unsets any verbose (-v) options. -h A short help message. -V Show the version. EXIT CODE
rdup-up return a zero exit code on success, otherwise 1 is returned. AUTHOR
Written by Miek Gieben. REPORTING BUGS
Report bugs to <miek@miek.nl>. SEE ALSO
http:/www.miek.nl/projects/rdup/ is the main site of rdup. Also see rdup(1), rdup-tr(1) and rdup-backups(7). COPYRIGHT
Copyright (C) 2005-2010 Miek Gieben. This is free software. There is NO warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. Licensed under the GPL version 3. See the file LICENSE in the source distribution of rdup. 1.1.11 13 Dec 2008 RDUP-UP(1)
All times are GMT -4. The time now is 02:16 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy