Hello I am still working on my code..... The issue I faced is that i have to have 00 01 02 03 04 05 06 07 08 09 010 011 ...099 100. But my numbers are 1 2 3 4 5 ...How I can change it to different format? Moreover, my number is in the file....so basically it reads number in file compare and increment the number and rewrite file with new number But my piece of code gives me nothing lol
for example: file kuku.txt
cat kuku.txt
->2013081001
after running my code
cat kuku.txt
->2013081002
Every time we build an executable the date and time are put into the file, I need to run checksum on just the working lines.(IE, no header files)
Is this even possible, if so how would I go about it?
I am using a HP-UX server any help you can give me will be greatly appreciated.
Thanks (6 Replies)
Hello, I'm trying to retreive certain bits of info from a file.
the file contains a list like this
info1:info2:info3:info4
info1:info2:info3:info4
info1:info2:info3:info4
info1:info2:info3:info4
how do i pick out only info2 or only info3 without the others?
Thanks (11 Replies)
Hello,
I have a XML file as below and i would like to extract all the lines between <JOB & </JOB> for every such occurance. The number of lines between them is not fixed.
Anyways to do this awk?
============
<JOB APR="1" AUG="1" DEC="1" FEB="1" JAN="1" JUL="1" JUN="1" MAR="1" MAY="1"... (3 Replies)
hlow all,
i have file with wc -l file.txt is 3412112 line number
so I want to break these files into several parts with assumsi line
1-1000000 will be create part1.txt and
1000001-2000000 will create part2.txt and
2000001-3000000 will create part3.txt and
3000001-3412112 will create... (5 Replies)
I understand the individual pieces of the following (with one exception ..), but how does it all work as one?
find ${HOME}/reports/ -name surveyresult*.txt -exec ls -1 {} \; | /usr/xpg4/bin/grep -E \
"${HOME}/reports/surveyresult{14,14}.txt" | sort > ${ResultsFileList}
Find all files like... (1 Reply)
Hello All,
I have a file like this
Define schema flat_file_schema
(
a varchar(20)
,b varchar(30)
,c varchar(40)
);
(Insert into table (
a
,b
,c
) values
(
1
,2
,3
); (4 Replies)
Hello All,
I have a file like this
APPLY
( 'INSERT INTO brdcst_media_cntnt (
cntnt_id
,brdcst_media_cntnt_cd
,cntnt_prvdr_cd
,data_src_type_cd
,cntnt_titl_nm
,cntnt_desc
,batch_dt
,batch_id
) VALUES
(
:cntnt_id (3 Replies)
I am dealing with some app log, see example below:
22:16:13.601 ClientSession(905)--Connection(5)--SELECT GETDATE()
22:16:13.632 ClientSession(158)--Connection(5)--SELECT 1
22:16:13.632 ClientSession(848)--Connection(6735)--SELECT 1 So far I needed to collect certain column from it, such as... (3 Replies)
I have the string:
XXXX.YYYY_ZZZ.20180724.01.txt
I need to get rid of .txt and get full four parts
XXXX.YYYY_ZZZ.20180724.01
I did:
CTL=`echo XXXX.YYYY_ZZZ.20180724.01.txt | rev | cut -d"." -f4 | rev`
But got only YYYY_ZZZ
What should I do to get all four parts of that... (4 Replies)