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Full Discussion: ksh : need to get the 4 th line above and 2 nd below the matched pattern in the log file
Top Forums Shell Programming and Scripting ksh : need to get the 4 th line above and 2 nd below the matched pattern in the log file Post 302861675 by rpm120 on Wednesday 9th of October 2013 11:28:11 AM
Old 10-09-2013
Lightbulb ksh : need to get the 4 th line above and 2 nd below the matched pattern in the log file
I have a log file as given below
Code:
 
012/01/21 10:29:02  (111111)  Processing Job '23_369468343464564'
     2012/01/21 10:29:02  (111111)
     Making Job '23_369468343464564.0'...
     2012/01/21 10:29:04 (111111)
     Jobnumber '23_369468343464564' was successful 
     2012/01/21 10:29:04  (111111) 
Job has 123 Docs 234 Pgs 456 Lines 4 Errors
     2012/01/21 10:29:04  (111111)
     Total in Job: 123 documents using 29 KBytes

I want awk the 4th line above (i.e "012/01/21 10:29:02 (111111) Processing batch '23_369468343464564'") and 2nd line below (i.e Job has 123 Docs 234 Pgs 456 Lines 4 Errors ) the pattern

Code:
Jobnumber '23_369468343464564' was successful

Please help
 

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