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Full Discussion: Finding an average
Top Forums Shell Programming and Scripting Finding an average Post 302860941 by Akshay Hegde on Monday 7th of October 2013 03:25:56 PM
Old 10-07-2013
Quote:
Originally Posted by Manu1234567
Basically, I need to find average of numbers which are given like:
sh average file1 file (in files can be more than one number)
->10
sh average 5 7
->6
sh average /users/file
->5
echo 5 7 | sh average
6
So basically i wrote my code but it gives me error... I am pretty sure it has to work for first two cases at least.... But I stucked with my error messages ;(
this is my code:

Code:
sum=0
n=0
for i in $*
do
    if [ -f $i ]
    then
        while read line
        do

           n=` expr $n + 1 `
           sum=` expr $sum + $line `
                         done < $i

        else
           sum=` expr $sum + $i `
           n=` expr $n + 1 `
           fi


         done

          average=` expr $sum / $n `
          echo $average

Code:
you have to use bc and you also need to check argument exist or not

try

Code:
#!/bin/ksh

check(){
    if [ -z "$1" ];then echo "No user input exiting..";exit;fi
       }

check $1

sum=0
n=0
for i in $*
do
    if [ -f $i ]
    then
        while read line
        do
           n=` expr $n + 1 `
           sum=` expr $sum + $line `
        done < $i

        else
           sum=` expr $sum + $i `
           n=` expr $n + 1 `
           fi
done
    average=$(echo "scale=3; $sum/$n" | bc -l )
    echo $average


Last edited by Akshay Hegde; 10-07-2013 at 04:42 PM..
This User Gave Thanks to Akshay Hegde For This Post:
 

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