hey folks,
been awhile (actaully a long while) since i last touched C. And the 3 books i've read don't really have much about using time.h
Question:
How would i be able to assign a variable the value of the current date minus 2 mths, keeping in mind the yr.
IE. would like to see Nov.31/2001... (1 Reply)
I'm writing a ksh script in which I want to present the user with a choice of choosing any of the last 15 days. i.e., a list like the following:
20040510 (today)
20040509 (yesterday)
20040508
.
.
.
20040426
Is there an easy way to produce the date from x number of days ago other than... (3 Replies)
I need to achieve the following.....I seached the forum but could not find it...
This is I have in a file...
"CH","TIA","10/27/2006",000590
I need the date in the third field to be attached to fileas 20061027_test.txt
How do I do it. (6 Replies)
HI,
I'm comparing my file date with the system date and if both the dates are equal I'm doing some operation. I use two variables for these two dates. I use the following command in my query. if ....
But here the current date $cd shows 01 and filedate $fdate shows 1. The file is created on 1 of ... (6 Replies)
Hi Gurus,
How to minus 15 minuets from current system time.
For example if current time is " Wed Oct 14 12:12:38 BST 2009", i need "Wed Oct 14 11:57:38 BST 2009"
Thanks (2 Replies)
How can i print a future time, so i get current time by date "+%H:M" but how can i say add 20 minutes to the current time and display as I have just done for current time. (1 Reply)
I have a file with a field containing the following:
"7/3/2009 7:07:12 PM","xxxx"
I need to be able to split this field up into two into a different format with the time being converted into 24 hour:
so that i can get the following:
"20090307","19:07:12","xxxx" (8 Replies)
I have a data file. Seperated by "|". The 19 th filed is a date field that occurs like this
11/02/2001
i need to convert into the below format
2001-11-02
for e.g..
i/p
o/p should be
can somebody throw some light (5 Replies)
In my shell script I take date as a input parameter from command line in the format "21 Oct 2011" which would be
date +'%d %b %Y'
Now i need to do two things here.
1) Validate the date entered by user
2) Calculate yesterday's date from the input. So in this case it should be: "20 Oct 2011"... (9 Replies)
Hallo Team
I can perform the task manually but i would like to automate this process. ok here goes. I have a perl script which runs every Wednesday every week and the name of the script is check_19.pl
This is how the script looks like :
#!/usr/bin/perl -w
#use strict;
use DBI;
#... (1 Reply)
Discussion started by: kekanap
1 Replies
LEARN ABOUT DEBIAN
unshadow
UNSHADOW(8) System Manager's Manual UNSHADOW(8)NAME
unshadow - combines passwd and shadow files
SYNOPSIS
unshadow password-file shadow-file
DESCRIPTION
This manual page documents briefly the unshadow command, which is part of the john package. This manual page was written for the Debian
GNU/Linux distribution because the original program does not have a manual page. john, better known as John the Ripper, is a tool to find
weak passwords of users in a server.
The unshadow tool combines the passwd and shadow files so John can use them. You might need this since if you only used your shadow file,
the GECOS information wouldn't be used by the "single crack" mode, and also you wouldn't be able to use the '-shells' option. On a normal
system you'll need to run unshadow as root to be able to read the shadow file.
SEE ALSO john(8), mailer(8), unafs(8), unique(8).
The programs are documented fully by John's documentation, which should be available in /usr/share/doc/john or other location, depending on
your system.
AUTHOR
This manual page was written by Jordi Mallach <jordi@debian.org>, for the Debian GNU/Linux system (but may be used by others).
John the Ripper and mailer were written by Solar Designer <solar@openwall.com>. The complete list of contributors can be found in the CRED-
ITS file in the documentation directory.
john June 03, 2004 UNSHADOW(8)