hey folks,
been awhile (actaully a long while) since i last touched C. And the 3 books i've read don't really have much about using time.h
Question:
How would i be able to assign a variable the value of the current date minus 2 mths, keeping in mind the yr.
IE. would like to see Nov.31/2001... (1 Reply)
I'm writing a ksh script in which I want to present the user with a choice of choosing any of the last 15 days. i.e., a list like the following:
20040510 (today)
20040509 (yesterday)
20040508
.
.
.
20040426
Is there an easy way to produce the date from x number of days ago other than... (3 Replies)
I need to achieve the following.....I seached the forum but could not find it...
This is I have in a file...
"CH","TIA","10/27/2006",000590
I need the date in the third field to be attached to fileas 20061027_test.txt
How do I do it. (6 Replies)
HI,
I'm comparing my file date with the system date and if both the dates are equal I'm doing some operation. I use two variables for these two dates. I use the following command in my query. if ....
But here the current date $cd shows 01 and filedate $fdate shows 1. The file is created on 1 of ... (6 Replies)
Hi Gurus,
How to minus 15 minuets from current system time.
For example if current time is " Wed Oct 14 12:12:38 BST 2009", i need "Wed Oct 14 11:57:38 BST 2009"
Thanks (2 Replies)
How can i print a future time, so i get current time by date "+%H:M" but how can i say add 20 minutes to the current time and display as I have just done for current time. (1 Reply)
I have a file with a field containing the following:
"7/3/2009 7:07:12 PM","xxxx"
I need to be able to split this field up into two into a different format with the time being converted into 24 hour:
so that i can get the following:
"20090307","19:07:12","xxxx" (8 Replies)
I have a data file. Seperated by "|". The 19 th filed is a date field that occurs like this
11/02/2001
i need to convert into the below format
2001-11-02
for e.g..
i/p
o/p should be
can somebody throw some light (5 Replies)
In my shell script I take date as a input parameter from command line in the format "21 Oct 2011" which would be
date +'%d %b %Y'
Now i need to do two things here.
1) Validate the date entered by user
2) Calculate yesterday's date from the input. So in this case it should be: "20 Oct 2011"... (9 Replies)
Hallo Team
I can perform the task manually but i would like to automate this process. ok here goes. I have a perl script which runs every Wednesday every week and the name of the script is check_19.pl
This is how the script looks like :
#!/usr/bin/perl -w
#use strict;
use DBI;
#... (1 Reply)
Discussion started by: kekanap
1 Replies
LEARN ABOUT DEBIAN
unafs
UNAFS(8) System Manager's Manual UNAFS(8)NAME
unafs - script to warn users about their weak passwords
SYNOPSIS
unafs password-files cell-name
DESCRIPTION
This manual page documents briefly the unafs command, which is part of the john package. This manual page was written for the Debian
GNU/Linux distribution because the original program does not have a manual page. john, better known as John the Ripper, is a tool to find
weak passwords of users in a server.
The unafs tool gets password hashes out of the binary AFS database, and produces a file usable by John.
SEE ALSO john(8), mailer(8), unique(8), unshadow(8).
The programs are documented fully by John's documentation, which should be available in /usr/share/doc/john or other location, depending on
your system.
AUTHOR
This manual page was written by Jordi Mallach <jordi@debian.org>, for the Debian GNU/Linux system (but may be used by others).
John the Ripper and mailer were written by Solar Designer <solar@openwall.com>. The complete list of contributors can be found in the CRED-
ITS file in the documentation directory.
john June 03, 2004 UNAFS(8)