Hi how do i grep only a part of the line from a file from all the lines.
file:
asdfgh 543212376 nag
lkjh abhilash 543757858
How do i grep and print only 543212376 and 543757858
Can i grep something like 543* and print only that. (3 Replies)
Hello everyone,
I have been trying to get a list of all files containing a line of this type:
};#followed by anything
with any spaces (0 or more or 0 or more tabs) before the } and between each of the characters.
I have been trying this :
grep '*}*;*#*' *.c
but I have not been fully... (1 Reply)
Hi I have the following Input
--
-- TABLE: BUSINESS_UNIT
--
ALTER TABLE RATINGS.BUSINESS_UNIT ADD CONSTRAINT FK1_BUSINESS_UNIT
FOREIGN KEY (PEOPLESOFT_CHART_FIELD_VALUE_ID)
REFERENCES RATINGS.PEOPLESOFT_CHART_FIELD_VALUE(PEOPLESOFT_CHART_FIELD_VALUE_ID)
;
ALTER TABLE... (1 Reply)
I have a txt file with more than 10000 lines. There is a unique pattern which is scattered into the file. it starts with @9 and it has 15 characters. i need to grep them and display along with line numbers.
Eg: File - Test1
test message....
....
..
..
@9qwerty89
...test message... (8 Replies)
Hi,
I have got the below requirement. please suggest.
I have a file like,
Processing Item is:
/data/ing/cfg2/abc.txt
/data/ing/cfg3/bgc.txt
Processing Item is:
/data/cmd/for2/ght.txt
/data/kernal/config.klgt.txt
I want to process the above file to get the output file like,
... (5 Replies)
$ cat file.log
Message Number = : Sending message 10:50:16^|^reqhdr.dummyid^=^02^|^reqhdr.timezone^=^GMT+05:30^|^DUMMYREQUEST^=^BH||||||||||||||||||$BD|OL|C|V||DummyAcctNo|02||24/12/2011|ST_DDM|DDM||||||||reqUUID110612105016$BT||||||||||||||||||$] Length
I have the above line in the... (4 Replies)
here is what i want to achieve.. i have a file with below contents
cat fileName
blah blah blah
.
.DROP this
REJECT that
.
--sport 7800 -j REJECT --reject-with icmp-port-unreachable
--dport 7800 -j REJECT --reject-with icmp-port-unreachable
.
.
.
more blah blah blah
--dport 3306... (14 Replies)
Hi ,
I have a file where i have modifed certain things compared to original file . The difference of the original file and modified file is as follows.
# diff mir_lex.c.modified mir_lex.c.orig
3209c3209
< if(yy_current_buffer -> yy_is_our_buffer == 0) {
---
>... (5 Replies)
I have a file with a list of references towards the end and want to apply a grep for some string.
text ....
@unnumbered References
@sp 1
@paragraphindent 0
2017. @strong{Chalenski, D.A.}; Wang, K.; Tatanova, Maria; Lopez,
Jorge L.; Hatchell, P.; Dutta, P.; @strong{Small airgun... (1 Reply)
Discussion started by: kristinu
1 Replies
LEARN ABOUT DEBIAN
shtool-path
SHTOOL-PATH.TMP(1) GNU Portable Shell Tool SHTOOL-PATH.TMP(1)NAME
shtool-path - GNU shtool command dealing with shell path variables
SYNOPSIS
shtool path [-s|--suppress] [-r|--reverse] [-d|--dirname] [-b|--basename] [-m|--magic] [-p|--path path] str [str ...]
DESCRIPTION
This command deals with shell $PATH variables. It can find a program through one or more filenames given by one or more str arguments. It
prints the absolute filesystem path to the program displayed on "stdout" plus an exit code of 0 if it was really found.
OPTIONS
The following command line options are available.
-s, --suppress
Supress output. Useful to only test whether a program exists with the help of the return code.
-r, --reverse
Transform a forward path to a subdirectory into a reverse path.
-d, --dirname
Output the directory name of str.
-b, --basename
Output the base name of str.
-m, --magic
Enable advanced magic search for ""perl"" and ""cpp"".
-p, --path path
Search in path. Default is to search in $PATH.
EXAMPLE
# shell script
awk=`shtool path -p "${PATH}:." gawk nawk awk`
perl=`shtool path -m perl`
cpp=`shtool path -m cpp`
revpath=`shtool path -r path/to/subdir`
HISTORY
The GNU shtool path command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 1998 for Apache. It was later taken
over into GNU shtool.
SEE ALSO shtool(1), which(1).
18-Jul-2008 shtool 2.0.8 SHTOOL-PATH.TMP(1)