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Top Forums Shell Programming and Scripting (RHEL, Bash) List users and check if they have logged on during the last 2 months Post 302859783 by sea on Thursday 3rd of October 2013 09:22:44 PM
Old 10-03-2013
If the users are supposed to login localy, you could try (as root):
Code:
cat /etc/passwd|sed s,:,\ ,g|awk '{print $3" "$1}'|sort -r > var

while read line;do
    uid=$(echo $line|awk '{print $1}')
    usr=$(echo $line|awk '{print $2}')
    [[ $uid -ge 1000 ]] && \
        echo "User $usr, last login: $(ls -la /home/$usr/.xsession-errors|awk '{print $6$7}')"
done < var

Hope this helps
This User Gave Thanks to sea For This Post:
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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