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Top Forums Shell Programming and Scripting How to Grep than scan line below grep pattern Post 302859757 by CarloM on Thursday 3rd of October 2013 05:36:02 PM
Old 10-03-2013
If your awk supports multi-character record separators, you could do something like:
Code:
$ awk '/Apple/ {printf RS $1 OFS "Apple\n"}' RS="20130210" fruit
20130210154634 Apple
20130210171829 Apple


Last edited by CarloM; 10-03-2013 at 06:39 PM.. Reason: Fixed output format
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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