Hi All
How can i append a file name with a string
e.g.
Lets say i have a file called
ABC_TEST_1234_1.dat
and i want to append the file name with a lets say 100
so the output file should look like
ABC_100_TEST_1234_1.dat
i have aroung 9000 file in a directory and want to... (3 Replies)
I have a file like below
#GROUP A belongs to Asia
GROUP A jojh hans local admin
GROUP A gege fans michel jing jong
#GROUP U belongs to USA
GROUP U jeff goal hello world
My requirement is to grep for first apperence of GROUP A which is not commented and append my name to end of file.... (12 Replies)
Hi all,
I have a question..
Here is my requirement..I have 500 files in a path say /a/b/c
I have some numbers in a file which are comma seperated...and I wanted to check if the numbers are present in the FileName in the path /a/b/c..if the number is there in the file that is fine..but if... (1 Reply)
Right now, my code is:
s/Secondary Ins./Secondary Ins.\
1/g
It's adding a 1 as soon as it finds Secondary Ins.
Primary Ins.: MEDICARE B DMERC Secondary Ins.
1: CONTINENTAL LIFE INS
What I really want to achieve is having a 1 added on the next line that contain "Secondary Ins." It... (4 Replies)
Dear all,
I need your help, I have file like this:
file1:23456
01910964830098775635
34567
01942809546554654323
67589
26546854368698023653
09778
58716868568576876878
08675
86178546154065406546
08573
54165843543054354305
.
.file2:
23456 25
34567 26
67589 27 (2 Replies)
Hi Experts,
Is there a way to find a string in a file then append a character to that string then save the file or save to another file.
Here is an example.
>cat test.txt
NULL
NULL
NULL
9,800.00
NULL
1,234,567.01
I want to find all NON NULL String and add a dollar sign to those... (9 Replies)
Hi,
I need to replace and append a string in a text if grep is true. For eg:
grep ABC test.txt | grep -v '\.$' | awk {'print $4'} | sed "s/ ?
How do I replace all instances of "print $4" using sed with another sring? Eg of the string returned will be,
lx123
web222
xyz
Want to... (8 Replies)
Hi,
I have a File, which have multiple rows.
Like below
123456 Test1 FNAME JRW#$% PB MO Approver XXXXXX. YYYY
123457 Test2 FNAME JRW#$% PB MO Super XXXXXX. YYYY
123458 Test3 FNAME JRW#$% PB MO Approver XXXXXX. YYYY
I want to search a line which contains PB MO Approver and append... (2 Replies)
Hello
I would like to get know how to do this:
I got a big file (about 1GB) and I need to find a string (for instance by grep )
and then find all records in this file based on a string.
Thanks for advice.
Martin (12 Replies)
Discussion started by: mape
12 Replies
LEARN ABOUT MOJAVE
english5.18
English(3pm) Perl Programmers Reference Guide English(3pm)NAME
English - use nice English (or awk) names for ugly punctuation variables
SYNOPSIS
use English;
use English qw( -no_match_vars ) ; # Avoids regex performance penalty
# in perl 5.16 and earlier
...
if ($ERRNO =~ /denied/) { ... }
DESCRIPTION
This module provides aliases for the built-in variables whose names no one seems to like to read. Variables with side-effects which get
triggered just by accessing them (like $0) will still be affected.
For those variables that have an awk version, both long and short English alternatives are provided. For example, the $/ variable can be
referred to either $RS or $INPUT_RECORD_SEPARATOR if you are using the English module.
See perlvar for a complete list of these.
PERFORMANCE
NOTE: This was fixed in perl 5.20. Mentioning these three variables no longer makes a speed difference. This section still applies if
your code is to run on perl 5.18 or earlier.
This module can provoke sizeable inefficiencies for regular expressions, due to unfortunate implementation details. If performance matters
in your application and you don't need $PREMATCH, $MATCH, or $POSTMATCH, try doing
use English qw( -no_match_vars ) ;
. It is especially important to do this in modules to avoid penalizing all applications which use them.
perl v5.18.2 2014-01-06 English(3pm)