09-20-2013
That said maybe if you gave us more information on your environment we could suggest wiser solutions... all we know so far is 2 servers... (connected to a disk bay? seen bothe sides? OS? etc...)
Update---
And what application you are mentionning for I you may have more obvious solutions ( e.g. if its Web stuff ...) my concern was more about heavy stuff like applicaion running oracle with oracle RDBMS etc
Last edited by vbe; 09-20-2013 at 11:54 AM..
Reason: Update--
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RTIME(3) Linux Programmer's Manual RTIME(3)
NAME
rtime - get time from a remote machine
SYNOPSIS
#include <rpc/des_crypt.h>
int rtime(struct sockaddr_in *addrp, struct rpc_timeval *timep,
struct rpc_timeval *timeout);
DESCRIPTION
This function uses the Time Server Protocol as described in RFC 868 to obtain the time from a remote machine.
The Time Server Protocol gives the time in seconds since 00:00:00 UTC, 1 Jan 1900, and this function subtracts the appropriate constant in
order to convert the result to seconds since the Epoch, 1970-01-01 00:00:00 +0000 (UTC).
When timeout is non-NULL, the udp/time socket (port 37) is used. Otherwise, the tcp/time socket (port 37) is used.
RETURN VALUE
On success, 0 is returned, and the obtained 32-bit time value is stored in timep->tv_sec. In case of error -1 is returned, and errno is
set appropriately.
ERRORS
All errors for underlying functions (sendto(2), poll(2), recvfrom(2), connect(2), read(2)) can occur. Moreover:
EIO The number of returned bytes is not 4.
ETIMEDOUT
The waiting time as defined in timeout has expired.
NOTES
Only IPv4 is supported.
Some in.timed versions support only TCP. Try the example program with use_tcp set to 1.
Libc5 uses the prototype
int rtime(struct sockaddr_in *, struct timeval *, struct timeval *);
and requires <sys/time.h> instead of <rpc/auth_des.h>.
BUGS
rtime() in glibc 2.2.5 and earlier does not work properly on 64-bit machines.
EXAMPLE
This example requires that port 37 is up and open. You may check that the time entry within /etc/inetd.conf is not commented out.
The program connects to a computer called "linux". Using "localhost" does not work. The result is the localtime of the computer "linux".
#include <stdio.h>
#include <stdlib.h>
#include <errno.h>
#include <string.h>
#include <time.h>
#include <rpc/auth_des.h>
#include <netdb.h>
int use_tcp = 0;
char *servername = "linux";
int
main(void)
{
struct sockaddr_in name;
struct rpc_timeval time1 = {0,0};
struct rpc_timeval timeout = {1,0};
struct hostent *hent;
int ret;
memset(&name, 0, sizeof(name));
sethostent(1);
hent = gethostbyname(servername);
memcpy(&name.sin_addr, hent->h_addr, hent->h_length);
ret = rtime(&name, &time1, use_tcp ? NULL : &timeout);
if (ret < 0)
perror("rtime error");
else {
time_t t = time1.tv_sec;
printf("%s
", ctime(&t));
}
exit(EXIT_SUCCESS);
}
SEE ALSO
ntpdate(1), inetd(8)
COLOPHON
This page is part of release 3.53 of the Linux man-pages project. A description of the project, and information about reporting bugs, can
be found at http://www.kernel.org/doc/man-pages/.
GNU
2012-08-03 RTIME(3)