Getopts how to handle missing '-' in command line args. Post: 302854363

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Top Forums Shell Programming and Scripting Getopts how to handle missing '-' in command line args. Post 302854363 by gencon on Tuesday 17th of September 2013 09:53:13 AM

09-17-2013

Registered User

Quote:

Originally Posted by Don Cragun

The following rearrangement of your code ...snip... may help you understand how to use getopts.

Don,

What a thoroughly helpful and informative post, thank you so much. It has helped me to understand what's going on and to resolve my issue with ease. You obviously went to great effort to help me and that was very kind of you and it is greatly appreciated. Cheers Godfather. Smilie

Your example allowed me to resolve the situation by adding the following code immediately below the end of the getopts while loop.

Code:

# getopts stops processing args if it encounters an arg without a '-' prefix (unless it is an
# $OPTARG in which case processing continues). Check if any invalid args have been entered by
# working out how many args getopts has actually processed, shifting them off, and if more
# than 0 args remain then an invalid arg must have been entered.

let "numArgsProcessedByGetopts = OPTIND - 1"
shift "$numArgsProcessedByGetopts"
numArgsRemaining="$#"

if [ "$numArgsRemaining" -gt "0" ]; then
    Output_Error_Message "OptionInvalid"
    exit "$ExitStatusErrorSwitchInvalid"
fi

Thanks again.

One quick question... In your case statement you enclosed the patterns inside "()", I have only ever seen (or at least only ever noticed) a final ")". Is there any difference between the 2 styles of notation and, if so, what is the difference?

Code:

# e.g. Do "(c)" and "f)" notation differ in any way?

case $option in
    (c)  operationMode="CHECK"
         ;;
    f)   operationMode="FAST"
         ;;
esac

Last edited by gencon; 09-17-2013 at 01:24 PM..

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