Hi,
I want to know how to change this string to date format
20061102122042 to 02-11-2006 12:20:42
or 02-Nov-2006 12:20:42
Please let me know at the earliest.Thanks in advance.
Regards,
Preetham R. (3 Replies)
I know the command date +"%Y%m%d" can change today's date to digit format as below .
$date +"%Y%m%d"
20071217
it works fine .
now I want to do it back . If I have a file like below, (in the file , there are three lines, and each line have ; sign , after the ; sign is the date ) , I... (4 Replies)
Hi All,
this is my second post, last post reply was very helpful.
I have a data that has date in DD/MM/YYYY (07/11/2008) format i want to replace the backslash by a dot(.) so that my awk script can read it inside the C shell script that i have written.
i want to change 07/11/2008 to... (3 Replies)
Hi guys,
I have a text file with lots of lines like this:
MCOGT23R27815 27/07/07 27/05/09
SO733AM0235 30/11/07 30/11/10
NL123403N 04/03/08 04/03/11
0747AM7474 04/04/08 04/04/11
I want to change each line so the date format looks like this:
MCOGT23R27815 07/07/27 09/05/27 ... (7 Replies)
Dear Friends,
Need your help once again,
I have a variable ( e.g. ${i}) whoch has date in MM/DD/YYYY (E.g. 12/31/2011) format.
I want to change it to DD/MM/YYYY (e.g. 31/12/2011) format.
Request you to guide me as we are unable to do the same.
Thanks in advance
Anu. (1 Reply)
Hi,
I have the variable "$date_update" in that form:
2011-12-31T13:00:09Z and I would like to change it to
31/12/2011 13:00:09 (Date and Time separated by a blank).
Does anyone has a simple solution for that? (using Korn Shell)
Cheers
Jurgen (4 Replies)
Hi all,
I have a file that every line starts with the date and time. The format is like YYYYMMDDHHMM and I woulk like to change it to MM/DD/YY<space>HH:MM.
I tried to figure out a way to do it with sed, but I don't know how I could reorganize the digits of the first format. Does anyone have any... (1 Reply)
Hi,
I was looking for a script to change the date from one format to other. A search in the forum gave me the below script as a result.
#! /bin/ksh
format=YYYYMMDD
YEAR=${format%????}
DAY=${format#??????}
MON=${format#$YEAR}
MON=${MON%$DAY}
echo $MON/$DAY/$YEAR
I got it... (2 Replies)
Discussion started by: prithvirao17
2 Replies
LEARN ABOUT MOJAVE
uri::url5.18
URI::URL(3) User Contributed Perl Documentation URI::URL(3)NAME
URI::URL - Uniform Resource Locators
SYNOPSIS
$u1 = URI::URL->new($str, $base);
$u2 = $u1->abs;
DESCRIPTION
This module is provided for backwards compatibility with modules that depend on the interface provided by the "URI::URL" class that used to
be distributed with the libwww-perl library.
The following differences exist compared to the "URI" class interface:
o The URI::URL module exports the url() function as an alternate constructor interface.
o The constructor takes an optional $base argument. The "URI::URL" class is a subclass of "URI::WithBase".
o The URI::URL->newlocal class method is the same as URI::file->new_abs.
o URI::URL::strict(1)
o $url->print_on method
o $url->crack method
o $url->full_path: same as ($uri->abs_path || "/")
o $url->netloc: same as $uri->authority
o $url->epath, $url->equery: same as $uri->path, $uri->query
o $url->path and $url->query pass unescaped strings.
o $url->path_components: same as $uri->path_segments (if you don't consider path segment parameters)
o $url->params and $url->eparams methods
o $url->base method. See URI::WithBase.
o $url->abs and $url->rel have an optional $base argument. See URI::WithBase.
o $url->frag: same as $uri->fragment
o $url->keywords: same as $uri->query_keywords
o $url->localpath and friends map to $uri->file.
o $url->address and $url->encoded822addr: same as $uri->to for mailto URI
o $url->groupart method for news URI
o $url->article: same as $uri->message
SEE ALSO
URI, URI::WithBase
COPYRIGHT
Copyright 1998-2000 Gisle Aas.
perl v5.18.2 2012-02-11 URI::URL(3)