Hi Experts,
My requirement is to read the csv file and need to remove if any line break in it.
sample data:
Row1: "Oslo, Symra kino",Oslo,130-7,Symra 1,130-7-91
Row2:"Tønsberg, Brygga Kino SF",Tønsberg,202-1,
Tønsberg SF 4,202-1-4
Expected data:
Row1: "Oslo, Symra... (6 Replies)
I have an awk script to find the maximum value of the 2nd column of a 2 column datafile, but I need to find the top 5 maximum values of the 2nd column.
Here is the script that works for the maximum value.
awk 'BEGIN { subjectmax=$1 ; max=0} $2 >= max {subjectmax=$1 ; max=$2} END {print... (3 Replies)
Is there an awk script that can easily perform the following operation?
I have a data file that is in the format of
1944-12,5.6
1945-01,9.8
1945-02,6.7
1945-03,9.3
1945-04,5.9
1945-05,0.7
1945-06,0.0
1945-07,0.0
1945-08,0.0
1945-09,0.0
1945-10,0.2
1945-11,10.5
1945-12,22.3... (3 Replies)
Hello Members,
I have a csv file in the format below. Need help with awk statement to break nth column into 3 separate columns and export the changes to new file.
input file --> file.csv
cat file.csv|less
"product/fruit/mango","location/asia/india","type/alphonso"
need output in... (2 Replies)
Hi,
i need to remove mth and nth column from a csv file. here m and n is not a specific number. it is a variable
ex.
m=2
n=5
now i need to remove the 2nd and 5th line.. Please help how to do that.
Thanks!!! (18 Replies)
Hi, I am newbie in shell script.
I need your help to solve my problem.
Firstly, I have 2 files of csv and i want to compare of the contents then the output will be written in a new csv file.
File1:
SourceFile,DateTimeOriginal
/home/intannf/foto/IMG_0713.JPG,2015:02:17 11:14:07... (8 Replies)
I wanted to search for a string and replace it with other string from nth column of a file which is comma seperated which I am able to do with below
# For Comma seperated file without quotes
awk 'BEGIN{OFS=FS=","}$"'"$ColumnNo"'"=="'"$PPK"'"{$"'"$ColumnNo"'"="'"$NPK"'"}{print}' ${FileName} ... (5 Replies)
Hello everyone,
I am using ksh on Solaris 10 and I'm gathering data in a CSV file that looks like this:
20170628-23:25:01,1,0,0,1,1,1,1,55,55,1
20170628-23:30:01,1,0,0,1,1,1,1,56,56,1
20170628-23:35:00,1,0,0,1,1,2,1,57,57,2
20170628-23:40:00,1,0,0,1,1,1,1,58,58,2... (6 Replies)
Discussion started by: ejianu
6 Replies
LEARN ABOUT PHP
cubrid_column_types
CUBRID_COLUMN_TYPES(3) 1 CUBRID_COLUMN_TYPES(3)cubrid_column_types - Get column types in resultSYNOPSIS
array cubrid_column_types (resource $req_identifier)
DESCRIPTION
The cubrid_column_types(3) function gets column types of query results by using $req_identifier.
PARAMETERS
o $req_identifier
-Request identifier.
RETURN VALUES
Array of string values containing the column names, when process is successful.
FALSE, when process is unsuccessful.
EXAMPLES
Example #1
cubrid_column_types(3) example
<?php
$conn = cubrid_connect("localhost", 33000, "demodb", "dba");
$result = cubrid_execute($conn, "SELECT * FROM game WHERE host_year=2004 AND nation_code='AUS' AND medal='G'");
$column_names = cubrid_column_names($result);
$column_types = cubrid_column_types($result);
printf("%-30s %-30s %-15s
", "Column Names", "Column Types", "Column Maxlen");
for($i = 0, $size = count($column_names); $i < $size; $i++) {
$column_len = cubrid_field_len($result, $i);
printf("%-30s %-30s %-15s
", $column_names[$i], $column_types[$i], $column_len);
}
cubrid_disconnect($conn);
?>
The above example will output:
Column Names Column Types Column Maxlen
host_year integer 11
event_code integer 11
athlete_code integer 11
stadium_code integer 11
nation_code char 3
medal char 1
game_date date 10
SEE ALSO cubrid_column_names(3), cubrid_prepare(3), cubrid_execute(3).
PHP Documentation Group CUBRID_COLUMN_TYPES(3)