Thanks, but not all process is showing up in result.
Is there a way to list with seconds elapsed since a process started, rather than like day-hour:minute:seconds
Code:
1 1-00:00:00 init [3]
Should be like below. The above process is running for 1 day, 0 hour, 0 minutes, 0 seconds. So total seconds it has been running is 86400 seconds. So the ps result should show like below.
Ok, so I know there's a way to do this, but I've been trying to find out all afternoon with no luck. I think it should print out something like this:
1 bin
2 daemon
6 duo
Where the numbers on the left are the number of processes being run by the user whose name is listed on the right. Is... (4 Replies)
Hi,
Can any one help me on this.
How to capture the running process for two hours with an interval of 10 sec.
Thanks in andvance
Double post, continued here, thread closed (0 Replies)
Hi Experts,
Please help me in this.
I am trying this code on AIX 5.3.
I need list of jobs that executed in last 4 hours.
I have a schedule on this script - cron executes it and sends mail to me for every 2 hours.
I have a Job time and have around 100 jobs those execute daily.
What all i need... (2 Replies)
Hi All,
new to the forum and new to Unix but I have an issue which is annoying on a new level. I have included a short and full version for anyone needing more information.
Short Version
I am running a set of scripts that work and run fine. one of the scripts arranges the first... (4 Replies)
I have unix epoch time 1441678454803, Can you please help me to print this time in below format ?
DAY,HOUR,MIN,SEC
Appreciate your help!!!
Thanks,
Prince (7 Replies)
Hi,
Is it possible to display processes which have been running for more than a 5hrs using a variation of the ps -ef command?
Regards,
Manny (5 Replies)
HI
can someone help me to check the process running more than 2 hours.
I have the below command which shows the time and process id, however, I only need the processes running more than 2 hours. (8 Replies)
Discussion started by: Vinod
8 Replies
LEARN ABOUT DEBIAN
unparse_time_approx
PARSE_TIME(3) BSD Library Functions Manual PARSE_TIME(3)NAME
parse_time, print_time_table, unparse_time, unparse_time_approx, -- parse and unparse time intervals
LIBRARY
The roken library (libroken, -lroken)
SYNOPSIS
#include <parse_time.h>
int
parse_time(const char *timespec, const char *def_unit);
void
print_time_table(FILE *f);
size_t
unparse_time(int seconds, char *buf, size_t len);
size_t
unparse_time_approx(int seconds, char *buf, size_t len);
DESCRIPTION
The parse_time() function converts a the period of time specified in into a number of seconds. The timespec can be any number of <number
unit> pairs separated by comma and whitespace. The number can be negative. Number without explicit units are taken as being def_unit.
The unparse_time() and unparse_time_approx() does the opposite of parse_time(), that is they take a number of seconds and express that as
human readable string. unparse_time produces an exact time, while unparse_time_approx restricts the result to only include one units.
print_time_table() prints a descriptive list of available units on the passed file descriptor.
The possible units include:
second, s
minute, m
hour, h
day
week seven days
month 30 days
year 365 days
Units names can be arbitrarily abbreviated (as long as they are unique).
RETURN VALUES
parse_time() returns the number of seconds that represents the expression in timespec or -1 on error. unparse_time() and
unparse_time_approx() return the number of characters written to buf. if the return value is greater than or equal to the len argument, the
string was too short and some of the printed characters were discarded.
EXAMPLES
#include <stdio.h>
#include <parse_time.h>
int
main(int argc, char **argv)
{
int i;
int result;
char buf[128];
print_time_table(stdout);
for (i = 1; i < argc; i++) {
result = parse_time(argv[i], "second");
if(result == -1) {
fprintf(stderr, "%s: parse error
", argv[i]);
continue;
}
printf("--
");
printf("parse_time = %d
", result);
unparse_time(result, buf, sizeof(buf));
printf("unparse_time = %s
", buf);
unparse_time_approx(result, buf, sizeof(buf));
printf("unparse_time_approx = %s
", buf);
}
return 0;
}
$ ./a.out "1 minute 30 seconds" "90 s" "1 y -1 s"
1 year = 365 days
1 month = 30 days
1 week = 7 days
1 day = 24 hours
1 hour = 60 minutes
1 minute = 60 seconds
1 second
--
parse_time = 90
unparse_time = 1 minute 30 seconds
unparse_time_approx = 1 minute
--
parse_time = 90
unparse_time = 1 minute 30 seconds
unparse_time_approx = 1 minute
--
parse_time = 31535999
unparse_time = 12 months 4 days 23 hours 59 minutes 59 seconds
unparse_time_approx = 12 months
BUGS
Since parse_time() returns -1 on error there is no way to parse "minus one second". Currently "s" at the end of units is ignored. This is a
hack for English plural forms. If these functions are ever localised, this scheme will have to change.
HEIMDAL October 31, 2004 HEIMDAL