The BEGIN section is a section of code awk reads before it reads any files.
It is not running shell code, which is why it looks so different, it's running awk code, it's its own language.
If yc=0 and yb=4, it loops 5 times, with y=0, y=1, y=2, y=3, y=4, y=5, following the mathematical formula given to calculate new results for x, then prints the coordinates.
I am beginner in awk
awk 'BEGIN{for(i=1;(getline<"opnoise")>0;i++) arr=$1}{print arr}'
In the above script, opnoise is a file, I am reading it into an array and then printing the value corresponding to index 20. Well this is not my real objective, but I have posted this example to describe... (1 Reply)
Hi Experts,
The question may look very silly by seeing the title, but please have a look at it clearly.
I have a text file where the first 5 columns in each row were supposed to be attributes of a sample(like sample name, number, status etc) and the next 25 columns are parameters on which... (3 Replies)
Dear People,
My query is:
have a file, which looks likes this:
10 20 30 40 50
1 2 3 4 5
100 200 300 400 500
what i need is: "PRINT EACH LINE TO AN UNIQUE FILE"
desired output:
file 1
10 20 30 40 50
file 2
1 2 3 4 5 (3 Replies)
Hi!
I have a strange behaviour from sed and awk, but I'm not sure, if I'm doing something wrong:
I have a list of words, where I want to add the following string at the end of each line:
\;\;\;\;0\;1
I try like this:
$ cat myfile | awk '{if ( $0 != "" ) print $0"\;\;\;\;0\;1"}'
Result:... (5 Replies)
I found that
echo "aaa" | awk '{print ",\\";}'
works, and it will give "\".
but
ddd=`echo "aaa" | awk '{print ",\\";}'`; echo $ddd
will not work.
Could anyone tell me why? thank you. (8 Replies)
Hi,
I have written below script to begin if the line has n
#!/bin/ksh
/usr/xpg4/bin/awk {/ n / 'BEGIN {X = "01"; X = "02"; X = "03"; X = "04";
X = "05"; X = "06"; X = "07"; X = "08";
X ="09"; X = "10"; X = "11"; X = "12"; };}
NR > 1 {print $1 "\t" $5 "," X "," $6 " " $7}'} input.txt |... (9 Replies)
My code fails to do anything if I've BEGIN block in it:
Run the awk script as:
awk -f ~/bin/sum_dupli_gene.awk make_gene_probe.txt
#!/usr/bin/awk -f
BEGIN {
print ARGV
#--loads of stuff
}
END{
#more stuff
} (14 Replies)
Example:
I have files in below format
file 1:
zxc,133,joe@example.com
cst,222,xyz@example1.com
File 2 Contains:
hxd
hcd
jws
zxc
cst
File 1 has 50000 lines and file 2 has around 30000 lines :
Expected Output has to be :
hxd
hcd
jws (5 Replies)
Discussion started by: TestPractice
5 Replies
LEARN ABOUT LINUX
shtool-path
SHTOOL-PATH.TMP(1) GNU Portable Shell Tool SHTOOL-PATH.TMP(1)NAME
shtool-path - GNU shtool command dealing with shell path variables
SYNOPSIS
shtool path [-s|--suppress] [-r|--reverse] [-d|--dirname] [-b|--basename] [-m|--magic] [-p|--path path] str [str ...]
DESCRIPTION
This command deals with shell $PATH variables. It can find a program through one or more filenames given by one or more str arguments. It
prints the absolute filesystem path to the program displayed on "stdout" plus an exit code of 0 if it was really found.
OPTIONS
The following command line options are available.
-s, --suppress
Supress output. Useful to only test whether a program exists with the help of the return code.
-r, --reverse
Transform a forward path to a subdirectory into a reverse path.
-d, --dirname
Output the directory name of str.
-b, --basename
Output the base name of str.
-m, --magic
Enable advanced magic search for ""perl"" and ""cpp"".
-p, --path path
Search in path. Default is to search in $PATH.
EXAMPLE
# shell script
awk=`shtool path -p "${PATH}:." gawk nawk awk`
perl=`shtool path -m perl`
cpp=`shtool path -m cpp`
revpath=`shtool path -r path/to/subdir`
HISTORY
The GNU shtool path command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 1998 for Apache. It was later taken
over into GNU shtool.
SEE ALSO shtool(1), which(1).
18-Jul-2008 shtool 2.0.8 SHTOOL-PATH.TMP(1)