I am attempting to ssh to a server and grab the line from /etc/group if it contains a specific GID.
Example line from /etc/group:
Run locally on <host>:
Attempt to ssh to <host> and execute:
Enclosing the command in single or double quotes gives the same error:
I figure it has to have something to do with the expansion of $3 before the command is passed to <host> but I can't figure out how to protect it.
can anyone see the awk syntax error near line 1? I keep getting this error and I'm not familiar with awk very well yet so it is hard for me to see the errors.
fyi: deleteuser* refers to files in the directory where each one ends with a different date
ls -1 /mfupload/prod02/ftp/deleteuser* |... (12 Replies)
Due to some syntax error, my below code is not working.
#!/usr/bin/ksh
nawk '
BEGIN {
cur_val=0; cur_zero=0; cur_nine=0;
sum_zero=0; sum_nine=0;
}
/^/ {
cur_val=substr($0,5,2);
if("cur_val" == "0")
{
... (3 Replies)
hi there
i write one awk script file in shell programing
the code is related to dd/mm/yy to month, day year format
but i get an error
please can anybody help me out in this problem ??????
i give my code here including error
awk `
# date-month -- convert mm/dd/yy to month day,... (2 Replies)
Hi, I can't see what is wrong with the following command.
I am extracting a dollar amount (AMT_REJ, 6th field) from a comma delimited record and need to output it as numeric, removing the $sign and decimal point and output to another file. Everything seems to work except the $ sign which I need... (1 Reply)
Hi All,
I wrote a simple script.sh program
for i in seq (22)
do awk '$1==${i}' file1.txt|awk '{print $2}'> file${i}_study.txt
done
and then run it
%bash
%chmod +x script.sh
% ./script.sh
Give me error
awk: $1==${i}
awk: ^ syntax error
Do you have any idea why... (3 Replies)
I have been asked to look at a problem with implementing SSH on an HP-UX server which a colleague has set up. Users connect through PuTTY. When I try to establish a connection I see the following message:
Usage: -ssh host
Options:
-l user Log in using this user name.
-n ... (6 Replies)
Could somebody gently point out the error of my ways in the below (the flu I'm fighting might be contributing to my current haplessness)
awk -F="\t" \
'{
for (i = 1; i <= NR; i++);
FNR == i;
{
if (length($3) < 56 && length($1) > 56)
$1=($1" "$2); $2=$3; $3=$4;
... (1 Reply)
I know the below code worked, but the syntax appears to be wrong and I can not seem to correct it. Thank you :).
awk 'FNR==NR {E; next }>$3 in E {print $3, $5}' medical_exome__genes.txt RefSeqGene.txt > update.txt
awk: cmd. line:1: FNR==NR {E; next }>$3 in E {print $3, $5}
awk: cmd.... (2 Replies)
awk -F, ' NR>1 {
BEGIN{
chr=$2
}
END{
for (k in chr) {print k}
}
} ' $gene_file
I've a really simple code. I want to store gene name and it's chromosome and in the end print them.
I'm skipping line one as it contains headers.
But I don't know why I get error as: (2 Replies)
Discussion started by: genome
2 Replies
LEARN ABOUT CENTOS
ssh-ldap-helper
SSH-LDAP-HELPER(8) BSD System Manager's Manual SSH-LDAP-HELPER(8)NAME
ssh-ldap-helper -- sshd helper program for ldap support
SYNOPSIS
ssh-ldap-helper [-devw] [-f file] [-s user]
DESCRIPTION
ssh-ldap-helper is used by sshd(1) to access keys provided by an LDAP. ssh-ldap-helper is disabled by default and can only be enabled in the
sshd configuration file /etc/ssh/sshd_config by setting AuthorizedKeysCommand to ``/usr/libexec/openssh/ssh-ldap-wrapper''.
ssh-ldap-helper is not intended to be invoked by the user, but from sshd(8) via ssh-ldap-wrapper.
The options are as follows:
-d Set the debug mode; ssh-ldap-helper prints all logs to stderr instead of syslog.
-e Implies -w; ssh-ldap-helper halts if it encounters an unknown item in the ldap.conf file.
-f ssh-ldap-helper uses this file as the ldap configuration file instead of /etc/ssh/ldap.conf (default).
-s ssh-ldap-helper prints out the user's keys to stdout and exits.
-v Implies -d; increases verbosity.
-w ssh-ldap-helper writes warnings about unknown items in the ldap.conf configuration file.
SEE ALSO sshd(8), sshd_config(5), ssh-ldap.conf(5),
HISTORY
ssh-ldap-helper first appeared in OpenSSH 5.5 + PKA-LDAP .
AUTHORS
Jan F. Chadima <jchadima@redhat.com>
BSD April 29, 2010 BSD