Thanks for the reply.

This seems to work,

Code:

@echo off
SET PATH = C:\cygwin\bin;%PATH%;
start "" /b C:\cygwin\bin\mintty.exe -i /Cygwin-Terminal.ico -

Apparently the /b flag opens the program in the same console. I guess that means that mintty inherits the change. If I run this bat and enter "echo $PATH" in the terminal I get,

/usr/local/bin:/usr/bin:/cygdrive/c/Program Files/Intel/iCLS Client:/cygdrive/c/WINDOWS/system32:/cygdrive/c/WINDOWS:/cygdrive/c/WINDOWS/System32/Wbem:/cygdrive/c/Program Files/Intel/Intel(R) Management Engine Components/DAL:/cygdrive/c/Program Files/Intel/Intel(R) Management Engine Components/IPT:/cygdrive/c/Program Files/Emergent 5.3.9 (32-bit)/bin:/usr/lib/lapack

It appears as if the cygwin directories are in the path ( /usr/local/bin:/usr/bin: ). I have no real way of knowing if the is the correct /usr/local/bin since cygwin has truncated the path names.

The problem is that if I start a terminal from the normal shortcut (not using the bat file above) I get the same information when I echo $PATH. I also don't know if I need to start every terminal and every program from such a bat file.

I think it might make more sense to have the cygwin1 install location always be in the path as an environment variable since that is the one I use most often. If I need the cygwin2 install, I would need to run a bat file that would remove the cygwin1 install location from that path and then insert the cygwin2 install location for that session only.

Does that make sense???

LMHmedchem