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Top Forums Shell Programming and Scripting Getting lines between patterns and perform operations Post 302844014 by Scrutinizer on Friday 16th of August 2013 06:07:04 AM
Old 08-16-2013
@Jotne, yes we could. Usually that would be too thin a solution, but in this case I guess it could sort of work... If they decided to sell Raspberries that would be regarded as a new record, but since it would not get printed the output would still be OK with this specific input...
 

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SPTSV(l)								 )								  SPTSV(l)

NAME
SPTSV - compute the solution to a real system of linear equations A*X = B, where A is an N-by-N symmetric positive definite tridiagonal matrix, and X and B are N-by-NRHS matrices SYNOPSIS
SUBROUTINE SPTSV( N, NRHS, D, E, B, LDB, INFO ) INTEGER INFO, LDB, N, NRHS REAL B( LDB, * ), D( * ), E( * ) PURPOSE
SPTSV computes the solution to a real system of linear equations A*X = B, where A is an N-by-N symmetric positive definite tridiagonal matrix, and X and B are N-by-NRHS matrices. A is factored as A = L*D*L**T, and the factored form of A is then used to solve the system of equations. ARGUMENTS
N (input) INTEGER The order of the matrix A. N >= 0. NRHS (input) INTEGER The number of right hand sides, i.e., the number of columns of the matrix B. NRHS >= 0. D (input/output) REAL array, dimension (N) On entry, the n diagonal elements of the tridiagonal matrix A. On exit, the n diagonal elements of the diagonal matrix D from the factorization A = L*D*L**T. E (input/output) REAL array, dimension (N-1) On entry, the (n-1) subdiagonal elements of the tridiagonal matrix A. On exit, the (n-1) subdiagonal elements of the unit bidiago- nal factor L from the L*D*L**T factorization of A. (E can also be regarded as the superdiagonal of the unit bidiagonal factor U from the U**T*D*U factorization of A.) B (input/output) REAL array, dimension (LDB,NRHS) On entry, the N-by-NRHS right hand side matrix B. On exit, if INFO = 0, the N-by-NRHS solution matrix X. LDB (input) INTEGER The leading dimension of the array B. LDB >= max(1,N). INFO (output) INTEGER = 0: successful exit < 0: if INFO = -i, the i-th argument had an illegal value > 0: if INFO = i, the leading minor of order i is not positive definite, and the solution has not been computed. The factoriza- tion has not been completed unless i = N. LAPACK version 3.0 15 June 2000 SPTSV(l)
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