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Top Forums Shell Programming and Scripting Store args passed in array but not the first 2 args Post 302843861 by in2nix4life on Thursday 15th of August 2013 11:29:54 AM
Old 08-15-2013
Code:
declare -a arr=("$@")
s=$(IFS=, eval 'echo "${arr[*]:(+2)}"')

echo "$s"

sh array.sh 1 2 3 4 5 6
3,4,5,6

 

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PARSE_STR(3)								 1							      PARSE_STR(3)

parse_str - Parses the string into variables

SYNOPSIS
void parse_str (string $str, [array &$arr]) DESCRIPTION
Parses $str as if it were the query string passed via a URL and sets variables in the current scope. Note To get the current QUERY_STRING, you may use the variable $_SERVER['QUERY_STRING']. Also, you may want to read the section on vari- ables from external sources. Note The magic_quotes_gpc setting affects the output of this function, as parse_str(3) uses the same mechanism that PHP uses to populate the $_GET, $_POST, etc. variables. PARAMETERS
o $str - The input string. o $arr - If the second parameter $arr is present, variables are stored in this variable as array elements instead. RETURN VALUES
No value is returned. EXAMPLES
Example #1 Using parse_str(3) <?php $str = "first=value&arr[]=foo+bar&arr[]=baz"; parse_str($str); echo $first; // value echo $arr[0]; // foo bar echo $arr[1]; // baz parse_str($str, $output); echo $output['first']; // value echo $output['arr'][0]; // foo bar echo $output['arr'][1]; // baz ?> SEE ALSO
parse_url(3), pathinfo(3), http_build_query(3), get_magic_quotes_gpc(3), urldecode(3). PHP Documentation Group PARSE_STR(3)
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