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Top Forums Shell Programming and Scripting Store args passed in array but not the first 2 args Post 302843857 by iaav on Thursday 15th of August 2013 11:10:22 AM
Old 08-15-2013
Store args passed in array but not the first 2 args

Store args passed in array but not the first 2 args.

Code:
# bash
declare -a arr=("$@")
s=$(IFS=, eval 'echo "${arr[*]}"')

echo "$s"

output:
 sh array.sh 1 2 3 4 5 6
1,2,3,4,5,6

Code:
Desired output:
sh array.sh 1 2 3 4 5 6
3,4,5,6

 

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GET_DEFINED_VARS(3)							 1						       GET_DEFINED_VARS(3)

get_defined_vars - Returns an array of all defined variables

SYNOPSIS
array get_defined_vars (void ) DESCRIPTION
This function returns a multidimensional array containing a list of all defined variables, be them environment, server or user-defined variables, within the scope that get_defined_vars(3) is called. RETURN VALUES
A multidimensional array with all the variables. EXAMPLES
Example #1 get_defined_vars(3) Example <?php $b = array(1, 1, 2, 3, 5, 8); $arr = get_defined_vars(); // print $b print_r($arr["b"]); /* print path to the PHP interpreter (if used as a CGI) * e.g. /usr/local/bin/php */ echo $arr["_"]; // print the command-line parameters if any print_r($arr["argv"]); // print all the server vars print_r($arr["_SERVER"]); // print all the available keys for the arrays of variables print_r(array_keys(get_defined_vars())); ?> SEE ALSO
isset(3), get_defined_functions(3), get_defined_constants(3). PHP Documentation Group GET_DEFINED_VARS(3)
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