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Top Forums Shell Programming and Scripting How to grep the required part from the string? Post 302843569 by sharsour on Wednesday 14th of August 2013 01:19:37 AM
Old 08-14-2013
How to grep the required part from the string?

Hi All,

I am trying to fetch the particular content from the result of grep command.

I am using

Code:
 
 
ps-ef |grep engine| awk '{print $6}'

above statement giving me

Code:
 
/opt/test/user/domain/CORPTEST/application/CacheScheduler/CacheScheduler-CacheScheduler

but I want

Code:
 
CacheScheduler-CacheScheduler

the end part of that output. Please suggest your valuable suggestions to get that required output.
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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