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Top Forums Shell Programming and Scripting How to remove mth and nth column from a file? Post 302841133 by konsolebox on Wednesday 7th of August 2013 03:34:32 AM
Old 08-07-2013
Quote:
Originally Posted by alister
I did not test your code, but looking at it there appears to be an off-by-one bug at i < last. last corresponds to the final field and it is never printed. It should be i <= last.
I remember finding this bug but probably my modification didn't went through.

Quote:
Originally Posted by alister
Aside from that, your implementation is also a bit overcomplicated. There is no need to explicitly split the record into an array when AWK has already split it into field variables for your convenience.

For portability, simplicty, and flexibility, I recommend:
Code:
{
    for (i=1; i<=NF; i++)
        if (i != m  &&  i != n)
            s = s OFS $i
    print substr(s, length(OFS)+1)
    s=""
}

Obviously, FS and OFS must be set to the appropriate values.
In the world of awk yes, but there's no way I would do that in C, and somehow doesn't make me want to do it in awk as well. If you're careful about speed you'll naturally not use that method despite appearing to be simpler. One could argue that that could be better but one would not.

Sometimes we think we could simplify things by minimizing our code but sometimes it just gets more bloated. Mine may not have been in its most optimized form but at least there's the balance. Yeah I know speed isn't crucial really but we have our opinions.

Edit: You could actually be correct about appending strings instead of calling multiple printfs since that could possibly cause multiple ioctl calls depending on awk's implementation, but I wouldn't consider print substr(s, length(OFS)+1).

Last edited by konsolebox; 08-07-2013 at 04:43 AM..
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