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Top Forums Shell Programming and Scripting Use sed to print first n lines and last n lines of an output. Post 302838933 by rajamadhavan on Tuesday 30th of July 2013 11:51:00 PM
Old 07-31-2013
Is your need to print them at one go using a single sed command ?

Can't you go with something like this ?

Code:
sed '3q' filename &&  sed -e :a -e '$q;N;4,$D;ba' filename

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TAIL(1) 						      General Commands Manual							   TAIL(1)

NAME
tail - deliver the last part of a file SYNOPSIS
tail [ +-number[lbc][rf] ] [ file ] tail [ -fr ] [ -n nlines ] [ -c nbytes ] [ file ] DESCRIPTION
Tail copies the named file to the standard output beginning at a designated place. If no file is named, the standard input is copied. Copying begins at position +number measured from the beginning, or -number from the end of the input. Number is counted in lines, 1K blocks or bytes, according to the appended flag or Default is -10l (ten ell). The further flag causes tail to print lines from the end of the file in reverse order; (follow) causes tail, after printing to the end, to keep watch and print further data as it appears. The second syntax is that promulgated by POSIX, where the numbers rather than the options are signed. EXAMPLES
tail file Print the last 10 lines of a file. tail +0f file Print a file, and continue to watch data accumulate as it grows. sed 10q file Print the first 10 lines of a file. SOURCE
/src/cmd/tail.c BUGS
Tails relative to the end of the file are treasured up in a buffer, and thus are limited in length. According to custom, option +number counts lines from 1, and counts blocks and bytes from 0. Tail is ignorant of UTF. TAIL(1)
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