[BASH] Gawk + MYSQL script Post: 302837573

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Top Forums Shell Programming and Scripting [BASH] Gawk + MYSQL script Post 302837573 by Zimny on Friday 26th of July 2013 05:39:57 AM

07-26-2013

Registered User

[BASH] Gawk + MYSQL script

Hello!

I've got script to write. It should read databases (names, volumes) from table testdatabase and compares it to actually existing databases in /var/lib/mysql/. If there is no informations about database in table - we should see information "There is no declared informations about database in table testdatabase." And if volume of database is too big - we should see information "Database database has too big actual size volume, it exceeds declared size in table testdatabase."

My problem is that even if there is existing database in /var/lib/mysql/ and I put informations about it in table testdatabase - I see statement - "There is no declared...".

Do you have any idea what am I doing wrong?

Code:

cd /var/lib/mysql/ || exit 1

gawk '
BEGIN {
   cmd = "mysql -u root -ppassword knowdatabases \"SELECT name, volume, date, description FROM testdatabase\""
   while ( cmd | getline ) {
      DATABASE[$1,1] = $2;
      DATABASE[$1,2] = $1;
   }
   close(cmd)
   
   cmd = "find /var/lib/mysql/ -maxdepth 1 -mindepth 1 -type d | xargs du -sm"
   while ( cmd | getline ) {
      VOL = $1;
      NAM = $2;
      if ( ! DATABASE[NAM,1] ) {
         print "There is no declared informations about " NAM " in table testdatabase."
      continue
      }
      if ( VOL > DATABASE[NAM,1] ) {
         print "Database " NAM " has too big actual size (" VOL "), it exceeds declared size in table testdatabase."
      continue
      }
   }
   close(cmd)
}
' /dev/null

Zimny

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mysqlbug

MYSQLBUG(1)						       MySQL Database System						       MYSQLBUG(1)

NAME

       mysqlbug - generate bug report

SYNOPSIS

       mysqlbug

DESCRIPTION

       This program enables you to generate a bug report and send it to Oracle Corporation. It is a shell script and runs on Unix.

       The normal way to report bugs is to visit http://bugs.mysql.com/, which is the address for our bugs database. This database is public and
       can be browsed and searched by anyone. If you log in to the system, you can enter new reports. If you have no Web access, you can generate
       a bug report by using the mysqlbug script.

       mysqlbug helps you generate a report by determining much of the following information automatically, but if something important is missing,
       please include it with your message.  mysqlbug can be found in the scripts directory (source distribution) and in the bin directory under
       your MySQL installation directory (binary distribution).

       Invoke mysqlbug without arguments:

	   shell> mysqlbug

       The script will place you in an editor with a copy of the report to be sent. Edit the lines near the beginning that indicate the nature of
       the problem. Then write the file to save your changes, quit the editor, and mysqlbug will send the report by email.

COPYRIGHT

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       at http://dev.mysql.com/doc/.

AUTHOR

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MySQL 5.1							    04/06/2010							       MYSQLBUG(1)