07-19-2013
Quote:
Originally Posted by
bakunin
You might want to read
this thread where i have covered exactly this problem.
I hope this helps.
bakunin
It isn't quite the same in this case because the input is not in sorted order and (since the month and day fields in the date are variable length [1 or 2 digits instead of always two digits with a leading 0 when needed] in the general case, the year is after the month and day, and there are different field separators needed to sort the parts of the date and the other field) the sort utility can't be used without a separate processing step to normalize the date.
If the OP doesn't care about the output order, this is trivial to do with awk. If the output needs to be sorted by year, month, day, and input column 6; the processing is more involved. I'm still waiting for radius to say whether or not output order matters.
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LEARN ABOUT PHP
cal_from_jd
CAL_FROM_JD(3) 1 CAL_FROM_JD(3)
cal_from_jd - Converts from Julian Day Count to a supported calendar
SYNOPSIS
array cal_from_jd (int $jd, int $calendar)
DESCRIPTION
cal_from_jd(3) converts the Julian day given in $jd into a date of the specified $calendar. Supported $calendar values are CAL_GREGORIAN,
CAL_JULIAN, CAL_JEWISH and CAL_FRENCH.
PARAMETERS
o $jd
- Julian day as integer
o $calendar
- Calendar to convert to
RETURN VALUES
Returns an array containing calendar information like month, day, year, day of week, abbreviated and full names of weekday and month and
the date in string form "month/day/year".
EXAMPLES
Example #1
cal_from_jd(3) example
<?php
$today = unixtojd(mktime(0, 0, 0, 8, 16, 2003));
print_r(cal_from_jd($today, CAL_GREGORIAN));
?>
The above example will output:
Array
(
[date] => 8/16/2003
[month] => 8
[day] => 16
[year] => 2003
[dow] => 6
[abbrevdayname] => Sat
[dayname] => Saturday
[abbrevmonth] => Aug
[monthname] => August
)
SEE ALSO
cal_to_jd(3), jdtofrench(3), jdtogregorian(3), jdtojewish(3), jdtojulian(3), jdtounix(3).
PHP Documentation Group CAL_FROM_JD(3)